hi scrath team i have some new blocks to show you also tell me if this is an duplicate

((0) ✕ (0) :: operators)

this will multiply the first input by second one.

( () ± () :: operators)

this will execute both plus and minus blocks in that order
thats all it see ya

() * ()

multiplies numbers.

What exactly do you want

() ± () :: operators reporter

to do?
You did not give a very precise description in the original post.

mlcreater wrote:

() * ()

multiplies numbers.

What exactly do you want

() ± () :: operators reporter

to do?
You did not give a very precise description in the original post.

i meant use plus and minus at the same time

coder_isaiyah11 wrote:

mlcreater wrote:

What exactly do you want

() ± () :: operators reporter

to do?
You did not give a very precise description in the original post.

i meant use plus and minus at the same time

A block cannot give two answers…

mlcreater wrote:

coder_isaiyah11 wrote:

mlcreater wrote:

What exactly do you want

() ± () :: operators reporter

to do?
You did not give a very precise description in the original post.

i meant use plus and minus at the same time

A block cannot give two answers…

it will add to the answer and then subtract from the awnser

coder_isaiyah11 wrote:

hi scrath team i have some new blocks to show you also tell me if this is an duplicate

((0) ✕ (0) :: operators)

this will multiply the first input by second one.

That already exists.

((0) * (0))

( () ± () :: operators)

this will execute both plus and minus blocks in that order

Adding and then subtracting the same number will only give you what you started with.

mlcreater wrote:

coder_isaiyah11 wrote:

mlcreater wrote:

What exactly do you want

() ± () :: operators reporter

to do?
You did not give a very precise description in the original post.

i meant use plus and minus at the same time

A block cannot give two answers…

I think they mean it adds it than subtracts it.

((12) ± (5)::operators) // 0

Or… forget that. If that was the case it would always output “0” .

() ✕ () :: operators reporter // this is the same as
(() * ()) // this.
() ± () :: operators reporter // for this one though,

it's useless.
a + b - b = a
meaning it would always return a, the number in the first input, no matter what you put in the second input (unless it's not a number). Whether it's negative, or not, it would always return a.

guess im just someone that will not help the community

coder_isaiyah11 wrote:

guess im just someone that will not help the community

Don't say that. It's just you need to think about different ideas that will help Scratch become better. This topic might help.

I'm going to close this thread. The first block appears to already be implemented; it's the existing multiplication block in the Scratch editor. As for the other one, it appears that an effective workaround is simply

((number) + (0))

as it requires the same number of blocks and the same number, if not less, characters to type in.

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