define convert (number) to hexadecimal //Run w/o Screen Refresh
if <(number) < [0]> then
convert ([abs v] of (number) :: operators) to hexadecimal // Convert the positive number to hexadecimal, then add a minus sign.
set [hex output v] to (join (-) (hex output))
else
set [hex output v] to []
if <not <(number) < (16)>>  then // Number will take more than one hexadecimal digit.
convert ([floor v] of ((number) / (16))) to hexadecimal // Convert everything before the last hexadecimal digit.
end
set [hex output v] to (join (hex output) (letter (((number) mod (16)) + (1)) of [0123456789ABCDEF])) // Join the preceding hexadecimal digits to the last one.
end

define hexidecimal (#) to decimal
set [output v] to [0]
set [i v] to [0]
if <(letter [1] of (#)) = [-]> then
change [i v] by [1]
end
repeat ((length of (#)) - (i))
change [i v] by [1]
change [output v] by (((item # of (letter (i) of (#))in [hex numbers v]) - [1]) * (round ([e^ v] of (([ln v] of [16]) * ((length of (#)) - (i)))::operators)))
end

NutOfCoco wrote:

Because of all this decimal to hexidecimal stuff I decided to make my own workaround (for the inverse):
-snip-

zispe wrote:

6.5 hexadecimal to decimal

Scratch can turn hexadecimal numbers (like FF) to decimal numbers (like 255) just by putting the hexadecimal in any math block. Make sure you include the special two characters 0x (zero then X) before the number. You can’t type this in number inputs, but if you get it from blocks like “ask and wait”, a variable, or the “join” block, it will work.

ask [what is the number in hexadecimal?] and wait
set [hexadecimal v] to (join [0x] (answer))
set [decimal v] to ((1) * (hexadecimal))
say (join (join (hexadecimal) [ in decimal is ]) (decimal))

CK840 wrote:

NutOfCoco wrote:

Because of all this decimal to hexidecimal stuff I decided to make my own workaround (for the inverse):
-snip-

We already have a workaround for converting hexadecimal to decimal.

zispe wrote:

6.5 hexadecimal to decimal

Scratch can turn hexadecimal numbers (like FF) to decimal numbers (like 255) just by putting the hexadecimal in any math block. Make sure you include the special two characters 0x (zero then X) before the number. You can’t type this in number inputs, but if you get it from blocks like “ask and wait”, a variable, or the “join” block, it will work.

ask [what is the number in hexadecimal?] and wait
set [hexadecimal v] to (join [0x] (answer))
set [decimal v] to ((1) * (hexadecimal))
say (join (join (hexadecimal) [ in decimal is ]) (decimal))

repeat ()

end

NutOfCoco wrote:

Here is a workaround for the if block:

repeat ()

end

this is a joke, but it works

chickenandcheesesand wrote:

Workaround Type:
Control/My Blocks
Workaround Title:
Immediately create (clones)
Method 1:

define immediately create (clones) clones //run without screen refresh
repeat(clones)
create clone of (myself v)

Description:
i think this might just be too simple or something

bitmap_caketin wrote:

NutOfCoco wrote:

Here is a workaround for the if block:

repeat ()

end

this is a joke, but it works

You do realise that these are workarounds for non-existent blocks?

NutOfCoco wrote:

bitmap_caketin wrote:

NutOfCoco wrote:

Here is a workaround for the if block:

repeat ()

end

this is a joke, but it works

You do realise that these are workarounds for non-existent blocks?