I am working on how to make exponents, and I found that their is no exponent block. would somebody be able to help me do this? This is my code so far:

when green flag clicked
forever
set [number one] to (pick random (3) to (10)
set [number two] to (pick random (3) to (10)
set [exponent] to (pick random (0) to (5)
set [sum of exponents and second number] to [number two]
if <not <<[exponent] = [0]> or <[exponent] = [1]>>> then
repeat (exponent)
set [sum of exponents and second number] to ((sum of exponents and second number) * (number two))
end
set [sum of exponents and second number] to ((sum of exponents and second number) / (number two))
set [sum of equation] to ((sum of exponents and second number) * (number one))
else
if <[exponent] = [0]> then
set [sum of equation] to (1)
else
if <[exponent] = [0]> then 
set [sum of equation] to ((number one) * (number two))
end
end
end
end

after all of that, I have an ask script that asks the player what the answer is, but I can't add that because the way I entered this didn't have the blocks.
also, this took forever to make, since I had to type this out and learn this new language that is only in the forums.

djollieboy11 wrote:

I am working on how to make exponents, and I found that their is no exponent block. would somebody be able to help me do this? This is my code so far:

when green flag clicked
forever
set [number one] to (pick random (3) to (10)
set [number two] to (pick random) (3) to (10)
set [exponent] to (pick random) (0) to (5)
set [sum of exponents and second number] to [number two]
if <not <<[exponent] = [0]> or <[exponent] = [1]>>> then
repeat (exponent)
set [sum of exponents and second number] to ((sum of exponents and second number) * (number two))
end
set [sum of exponents and second number] to ((sum of exponents and second number) / (number two))
set [sum of equation] to ((sum of exponents and second number) * (number one))
else
if <[exponent] = [0]> then
set [sum of equation] to (1)
else
if <[exponent] = [0]> then 
set [sum of equation] to ((number one) * (number two))
end
end
end
end

after all of that, I have an ask script that asks the player what the answer is, but I can't add that because the way I entered this didn't have the blocks.
also, this took forever to make, since I had to type this out and learn this new language that is only in the forums.
also sorry, I messed up a little in the code.

You mean something like this? Pretty simple to make: https://scratch.mit.edu/projects/1145491233/editor/

Okay, exponents can be calculated with

([e^ v] of (([ln v] of (base)::operators) * (exponent))::operators)

And root can be calculated with this

([e^ v] of (([ln v] of (base)::operators) / (root))::operators)

Okay, thank you all for the help! I really appreciate it.

NoUsername-King wrote:

Okay, exponents can be calculated with

([e^ v] of (([ln v] of (base)::operators) * (exponent))::operators)

And root can be calculated with this

([e^ v] of (([ln v] of (base)::operators) / (root))::operators)

I hope you see this, does root mean square root, and if so, square root of what?

SuperBee444 wrote:

(#5)

NoUsername-King wrote:

Okay, exponents can be calculated with

([e^ v] of (([ln v] of (base)::operators) * (exponent))::operators)

And root can be calculated with this

([e^ v] of (([ln v] of (base)::operators) / (root))::operators)

I hope you see this, does root mean square root, and if so, square root of what?

That can be used for any root, including a square root. A square root would look like this:

([e^ v] of (([ln v] of (base)::operators) / [2])::operators)

and a cube root would be a 3 and so on.

NoUsername-King wrote:

Okay, exponents can be calculated with

([e^ v] of (([ln v] of (base)::operators) * (exponent))::operators)

And root can be calculated with this

([e^ v] of (([ln v] of (base)::operators) / (root))::operators)

oh, theres a problem though. how do you do negative bases???

Dan_0319 wrote:

-snip-
oh, theres a problem though. how do you do negative bases???

Please avoid posting on other people's topics unless you are helping them. You should create a new topic instead.

Here is a fully functional exponent function that I made:

define (x) ^ (y)
if <(x::custom) > [0]> then
set [EXPONENT: output v] to ([e ^ v] of ((y::custom) * ([ln v] of (x::custom)::operators))::operators)
else
if <(x::custom) < [0]> then
if <(y::custom) = (round (y::custom))> then
set [EXPONENT: output v] to (((1) - ((2) * ((y::custom) mod (2)))) * ([e ^ v] of ((y::custom) * ([ln v] of (() - (x::custom))::operators))::operators))
else
set [EXPONENT: output v] to [NaN]
end
else
if <(y::custom) < [0]> then
set [EXPONENT: output v] to [NaN]
else
set [EXPONENT: output v] to (() + <(y::custom) = [0]>)
end
end
end

EDIT: I had to make so many edits to find what Scratch thought was inappropriate language. Apparently “p l e a s e d o n o t p o s t…” is unsuitable language? Man, Scratch really needs to fix the filter.

Dan_0319 wrote:

oh, theres a problem though. how do you do negative bases???

Look at my response to this discussion if you need to do negative bases.