Bella ⌁ A simple functional programming language ⌁ Written in Gleam!

W1-F1

I have a question about the new input function of bella;

If I enter left, It shows the message for the option left.

But if I enter right, I need to enter right twice before it shows the message for the option right.

It also does it when you enter an invalid option (else).

Is that because bella first reads If first, then Else if and then Else, but still showing the input of if when the code ‘jumps’ to else if?

It also does it when you enter an invalid option (else).

Is this a issue in my code or is that how the input function works?

The code:

Io.println("Hello, " + Io.readline("What is your name?"))
Io.println("You need to find your way home, you can go left or right.")
if (Io.readline("Enter your option:") == "left")
 Io.println("You fell and broke your leg. Game over.")

else if (Io.readline("Enter your option:") == "right")
 Io.println("You made it home! Congrats!")
else 
    Io.println("Please enter a valid option!")

Video

W1-F1

NFlex23 wrote:

W1-F1 wrote:

My text adventure game! Took me 10 minutes to make.

Io.println("Hello, " + Io.readline("What is your name?"))
Io.println("You need to find your way home, you can go left or right.")
if (Io.readline("Enter your option:") == "left")
 Io.println("You fell and broke your leg. Game over.")

else if (Io.readline("Enter your option:") == "right")
 Io.println("You made it home! Congrats!")
else (
    Io.println("Please enter a valid option!")
)

Very nice!

As a side note, you don't need the parenthesis after the final `else`.

Thank you!

PlNG_

W1-F1 wrote:
I have a question about the new input function of bella;

If I enter left, It shows the message for the option left.

But if I enter right, I need to enter right twice before it shows the message for the option right.

It also does it when you enter an invalid option (else).

Is that because bella first reads If first, then Else if and then Else, but still showing the input of if when the code ‘jumps’ to else if?

It also does it when you enter an invalid option (else).

Is this a issue in my code or is that how the input function works?

The code:
Io.println("Hello, " + Io.readline("What is your name?"))
Io.println("You need to find your way home, you can go left or right.")
if (Io.readline("Enter your option:") == "left")
 Io.println("You fell and broke your leg. Game over.")

else if (Io.readline("Enter your option:") == "right")
 Io.println("You made it home! Congrats!")
else 
    Io.println("Please enter a valid option!")
Video

Try letting a variable to the input:

Io.println("Hello, " + Io.readline("What is your name?"))
Io.println("You need to find your way home, you can go left or right.")
let input = Io.readline("Enter your option:") in

if (input == "left")
 Io.println("You fell and broke your leg. Game over.")
else if (input == "right")
 Io.println("You made it home! Congrats!")
else 
    Io.println("Please enter a valid option!")

W1-F1

PlNG_ wrote:
W1-F1 wrote:
I have a question about the new input function of bella;

If I enter left, It shows the message for the option left.

But if I enter right, I need to enter right twice before it shows the message for the option right.

It also does it when you enter an invalid option (else).

Is that because bella first reads If first, then Else if and then Else, but still showing the input of if when the code ‘jumps’ to else if?

It also does it when you enter an invalid option (else).

Is this a issue in my code or is that how the input function works?

The code:
Io.println("Hello, " + Io.readline("What is your name?"))
Io.println("You need to find your way home, you can go left or right.")
if (Io.readline("Enter your option:") == "left")
 Io.println("You fell and broke your leg. Game over.")

else if (Io.readline("Enter your option:") == "right")
 Io.println("You made it home! Congrats!")
else 
    Io.println("Please enter a valid option!")
Video
Try letting a variable to the input:
Io.println("Hello, " + Io.readline("What is your name?"))
Io.println("You need to find your way home, you can go left or right.")
let input = Io.readline("Enter your option:") in

if (input == "left")
 Io.println("You fell and broke your leg. Game over.")
else if (input == "right")
 Io.println("You made it home! Congrats!")
else 
    Io.println("Please enter a valid option!")

That worked! Thanks!

NFlex23

As I have alluded to a few times before, pattern matching has always been a goal of mine. Well, I've been working on it for a while now and I think it is almost ready to be merged! Please let me know what you think.

This is the PR: https://github.com/MystPi/bella/pull/8

Here is a little example of pattern matching (notice the `match` and `let` expressions):

let
  mylist =
    [1, 2, 3, 4, 5, 6, 7, 8, 9]

  map =
    list -> fn ->
      match list
        is [] then []
        is [first | rest] then
          [fn(first)] + map(rest, fn)

  reduce =
    list -> acc -> fn ->
      match list
        is [] then acc
        is [first | rest] then
          reduce(rest, fn(first, acc), fn)

  fold =
    list -> fn ->
      let [first | rest] = list in
      reduce(rest, first, fn)
in
(
  ; Squares
  map(mylist, x -> x * x) |> Io.println

  ; Sum
  fold(mylist, x -> a -> x + a) |> Io.println

  ; Length
  reduce(mylist, 0, x -> a -> a + 1) |> Io.println
)

And a “kitchen sink”:

let
  test = [1, 2, 3]
  [a, b, _] = test
  ^test = [1, 2, 3]
  y = 42
  42 = y
  x = false
  false = x
  ["add", a, b] = ["add", 50, 40]
  [x, ^Io.println(x * x), ^Io.println(x * x * x)] = [2, 4, 8]
  { name, cool: true } = { name: "MystPi", cool: true }
  { type: "dog", props: { name } } = { type: "dog", props: { name: "Bella" }}
  ^{ foo: true, bar: "blah" } = { foo: true, bar: "blah" }
  ^[1, 1 + 1, 1 + 1 + 1, 1 + 1 + 1 + 1] = [1, 2, 3, 4]
  [x, y | rest] = [1, 2, 3, 4]
  [x, ^(x + 1) as y, ^(x + 2) as z] = [1, 2, 3]
  ?Types.is_type("string") = "32"
in

Io.println("Everything matched successfully!")

Last edited by NFlex23 (Dec. 24, 2023 13:52:50)

W1-F1

NFlex23 wrote:
~snip~

Nice!

Discuss Scratch