(replace letters (3) through (6) of [banana] with [mboo] :: operators)

Seems pretty self-explanatory. It replaces the desired range of the string with a different substring. So, the example above would output “bamboo”.
The current workaround is a string parser which is too complex for its function and requires a TON of variables

set (i v) to (0)
delete (all v) of [list v]
repeat (length of (string :: grey))
change (i v) by (1)
add (letter (i) of (string :: grey)) to [list v]
end
set (i v) to (start value :: grey)
set (j v) to (replacement string :: grey)
...

ugh I'm too tired to write the rest of this script. but I know it deletes the range of letters specified,converts the replacement string to a list and inserts its letters at the same position, and then converts the list back into a string.

Edit: I just realized that an alternate workaround is to split the string, deleting the range specified, then convert both substrings to lists, and then do

join (string1) (replacement) (string2)

what happens if your second number is longer than the length of your first word

It treats it like it is the length of the word. If both numbers are larger than the length of the word, it function identically to the join block. If the numbers are the same, the replacement string is inserted at the position. If the second number is smaller than the first number, it treats the second number as the first and the first number as the second, similar to the

(pick random () to (10))

block.
If a number is negative, it treats it as 0.

what happens if your second number is longer than the length of your first word

Hi there! Your topic seems to be a duplicate of this post. To keep the conversation all in one place please use the link above, and before you make a new topic next time use this search tool to search for duplicates! I am now requesting a moderator to close this for you, scratch on! –Explosion–.

It is not a duplicate, it replaces more than one letter and has a different function in general

VectorV wrote:

It is not a duplicate, it replaces more than one letter and has a different function in general

Correct. You are describing a sub-string replace function where the other topic is a single character replace.