Gold is obviously the golden ratio.

Length of gold is the length of the variable Gold.

Round(gold) is Gold when it was rounded.

When I do anything with a* (*this) number with a large amount of decimal places it acts as if it were zero. Does anyone know why?


Any information you need will be given.

A “number” that long is going to be stored as string.

Scratch converts a string to the number 0 when a number is expected.

So, in this case,

(round (long string of digits))

is the same as

(round (0))

The explanation here may help.

Set gold to

((([sqrt v] of (5)) / (2)) + (0.5))

It gives you the same number.

TheHockeyist wrote:

Set gold to

((([sqrt v] of (5)) / (2)) + (0.5))

It gives you the same number.

It calculates to only 15 digits.

Mr-Glbstplwhttlgh wrote:

TheHockeyist wrote:

Set gold to

((([sqrt v] of (5)) / (2)) + (0.5))

It gives you the same number.

It calculates to only 15 digits.

It's a limitation of Scratch. You cannot enter for example, 1/3 exactly (0.33333…). Scratch has to stop because it can only hold so many digits before it's forced to round.

It assumes that it is a string because it has over 1900 decimals.