Discuss Scratch

17huntern
Scratcher
1 post

Exponents

Might I suggest an exponent operator block? I did eventually figure out that you can use 10^(log(x)*y) to convey x^y, but for convenience's sake, I would use the exponent block often.
cobraguy
Scratcher
1000+ posts

Exponents

There is already a topic for that. Please use that one.

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