Discuss Scratch

#1Yesterday 18:10:44
SandBean
New Scratcher
4 posts

Exponents

How to create exponents? I don't want to have to add a bunch of like, 3 * 3 * 3 * 3 and instead 3 ^ 4
#2Yesterday 19:16:24
maowMaowQN
Scratcher
100+ posts

Exponents

define exponent (base) (power)
set [digit v] to [1]
set [exponent v] to (base)
repeat (power)
set [exponent v] to ((exponent) * (base))
end
#3Yesterday 19:19:26
notdamienn3
Scratcher
29 posts

Exponents

maowMaowQN wrote:

define exponent (base) (power)
set [digit v] to [1]
set [exponent v] to (base)
repeat (power)
set [exponent v] to ((exponent) * (base))
end
You should be doing this instead.
define exponent (base) (power)
set [digit v] to [1]
set [exponent v] to (base)
repeat ((power) - (1))
set [exponent v] to ((exponent) * (base))
end
Without it, it will return base^power+1 instead of base^power.
Also, what is the digit variable there for?
#4Yesterday 19:20:16
maowMaowQN
Scratcher
100+ posts

Exponents

notdamienn3 wrote:

maowMaowQN wrote:

define exponent (base) (power)
set [digit v] to [1]
set [exponent v] to (base)
repeat (power)
set [exponent v] to ((exponent) * (base))
end
You should be doing this instead.
define exponent (base) (power)
set [digit v] to [1]
set [exponent v] to (base)
repeat ((power) - (1))
set [exponent v] to ((exponent) * (base))
end
Without it, it will return base^power+1 instead of base^power.
Also, what is the digit variable there for?
Oh yeah sorry I'm not too used to using the blocks feature and I accidentally put those
#5Yesterday 20:23:46
happywaffle0
Scratcher
100+ posts

Exponents

maowMaowQN wrote:

define exponent (base) (power)
set [digit v] to [1]
set [exponent v] to (base)
repeat (power)
set [exponent v] to ((exponent) * (base))
end

that works, but
([10^ v] of (([log v] of (base)::operators) * (exp))::operators)
is a better way to do it.

it works because log properties simplify this to
10^(exp*log(base)) -> 10^log(base^exp) ( ylogx = logx^y) -> base^exp


though some floating-point issues may occur so you may want to round() or ( of ()) that.

Last edited by happywaffle0 (Yesterday 20:25:33)

#6Yesterday 21:23:31
ClarkeGhost
Scratcher
100+ posts

Exponents

Yeah, happywaffle0's does script works perfect,

([10^ v] of (([log v] of (base)::operators) * (exponent))::operators)

But if you'd like more ways on how to do it, visit the Scratch Wiki Article on exponents.
#7Yesterday 22:05:11
SandBean
New Scratcher
4 posts

Exponents

Thx

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