([] in base (... v) :: operators)

(convert [] from base (... v) to base (... v) ::operators)

hedgehog_blue wrote:

This would be useful for changing the form of data for save codes or to be able to be stored in cloud variables. Currently, base conversion requires a slow process taking up multiple variables/custom blocks with a chance of becoming incorrect because of an inability to keep precision on larger numbers. Maybe allow the original base to be specified though.

(convert [] from base (... v) to base (... v) ::operators)

(round (join [0x] [10])) // 16
(round (join [0o] [10])) // 8
(round (join [0b] [10])) // 2

([A] from base (16) :: operators) // report a number
((10) to base (16) :: operators) // report a string

minor-edit wrote:

Scratch has built-in conversion from hexadecimal, octal, and binary to base ten.

(round (join [0x] [10])) // 16
(round (join [0o] [10])) // 8
(round (join [0b] [10])) // 2

Base conversion is a nice project.

None of the operators have three inputs. (Glide may be the only block, not counting lists.) In simpler blocks:

([A] from base (16) :: operators) // report a number
((10) to base (16) :: operators) // report a string

The second input, base, would be like on the repeat block.

chrdagos wrote:

minor-edit wrote:

Scratch has built-in conversion from hexadecimal, octal, and binary to base ten.

(round (join [0x] [10])) // 16
(round (join [0o] [10])) // 8
(round (join [0b] [10])) // 2

Base conversion is a nice project.

None of the operators have three inputs. (Glide may be the only block, not counting lists.) In simpler blocks:

([A] from base (16) :: operators) // report a number
((10) to base (16) :: operators) // report a string

The second input, base, would be like on the repeat block.

o.k, but a dropdown is better than having to type the b's and o's and x's.

do the bump! :: operators

(decode [FF] base (16) :: operators) // report a number
(encode (255) to base (16) :: operators) // report a string

define (n) in base (b)
set [result v] to []
set [num v] to ([abs v] of (n))
repeat until <(num)=[0]>
set [result v] to (join(letter(((num)mod(b))+(1))of[0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ])(result))
set [num v] to ([floor v] of ((num)/(b))
end
if <(n)<[0]> then
set [result v] to (join[-](result))
end

Seth_Zaw wrote:

Base-1 (unitary) isn't possible.

minor-edit wrote:

Same simpler blocks with new labels:

(decode [FF] base (16) :: operators) // report a number
(encode (255) to base (16) :: operators) // report a string

The input of base would have a dropdown like on the repeat block.

Seth_Zaw wrote:

Base-1 (unitary) isn't possible.
BTW, here's a workaround:

define (n) in base (b)
set [result v] to []
set [num v] to ([abs v] of (n))
repeat until <(num)=[0]>
set [result v] to (join(letter(((num)mod(b))+(1))of[0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ])(result))
set [num v] to ([floor v] of ((num)/(b))
end
if <(n)<[0]> then
set [result v] to (join[-](result))
end

chrdagos wrote:

Seth_Zaw wrote:

Base-1 (unitary) isn't possible.
BTW, here's a workaround:

define (n) in base (b)
set [result v] to []
set [num v] to ([abs v] of (n))
repeat until <(num)=[0]>
set [result v] to (join(letter(((num)mod(b))+(1))of[0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ])(result))
set [num v] to ([floor v] of ((num)/(b))
end
if <(n)<[0]> then
set [result v] to (join[-](result))
end

but this so-called “workaround” doesn't allow you to choose the base that you are converting FROM

minor-edit wrote:

Same simpler blocks with new labels:

(decode [FF] base (16) :: operators) // report a number
(encode (255) to base (16) :: operators) // report a string

The input of base would have a dropdown like on the repeat block.

(convert [FF] from base (16 v) to base (10 v)::operators)
(convert [255] from base (10 v) to base (16 v)::operators)

chrdagos wrote:

Seth_Zaw wrote:

Base-1 (unitary) isn't possible.

incorrect. base 1 is possible. however, it isn't practical because…

1 in unitary is 1
2 in unitary is 11
3 in unitary is 111
4 in unitary is 1111
and so on…

Sheep_maker wrote:

Could merge them into a single block:

(convert [FF] from base (16 v) to base (10 v)::operators)

minor-edit wrote:

None of the operators have three inputs. (Glide may be the only block, not counting lists.)

minor-edit wrote:

True, but the number of inputs would be atypical.