So, I have something where I need a sprite to clone, and then give its clone a new coordinate. How would I do this, and is it even possible?

The answer probably is local variables. They allow clones to have their own, unique copy of the variable, allowing it to be different for each clone.

Use these scripts (make sure you make identical costumes, and the number of costumes should equal the number of sprites you want):

switch costume to [1 v] // apply this to the Sprite you're cloning
create clone of [myself v]
switch costume to [2 v]
create clone of [myself v]
switch costume to [3 v]
create clone of [myself v]
...

when I start as a clone
... // this applies to all clones
if <(costume [number v] :: looks) = [1]> then
... // this applies only to the clone made with costume 1
end
if <(costume [number v] :: looks) = [2]> then
... // this applies only to the clone made with costume 2
end
if <(costume [number v] :: looks) = [3]> then
... // this applies only to the clone made with costume 3
end

This is my official 500th post!

what i found works is if when you clone them, turn them one degree each time. since scratch only allows 300 clones at once, and there's 360 degrees in a circle, you will not run into any problems. also, when you create it, you are going to have to have two lists: 1 for all the angles and the other one for the variables. here's some code for it:

when green flag clicked
repeat (...)
create clone of [myself v]
add (direction) to [ANGLES v]
add [YOUR VARIABLE] to [varibles v]
end

That is so smart!! Thank you!!

Also, do you know how to sense what another sprite's costume number is?

DragonFire973 wrote:

Also, do you know how to sense what another sprite's costume number is?

For a sprite just use the sensing block

([ v] of [Sprite1 v])

K, thanks.

hi this is my 1st time posting on forums

Welcome to the forums! Contrary to what my account says, I'm not new to scratch, and I can say sticking around is worth it. Just for future reference, try not to post on old threads, and try to keep posts on-topic. You can introduce yourself over here in the new scratchers forum: https://scratch.mit.edu/discuss/6/

May the force be with you!