<this sprite clicked?::sensing>

PixelYoshi wrote:

my_pup4life wrote:

Hopeijay wrote:

my_pup4life wrote:

is there a workaround for this:

set speed to (...):: sound

What do you want this block to do to what?

If you are talking about setting the speed of the sprite, this may help:

set speed to (...):: #7238a8

define set speed to (speed)
forever
move (speed) steps
end

I made it a sound block for a reason, its supposed to be the speed of the sound without the pitch changing

i don't think you can change the speed of a sound without the pitch changing. i think thats just how it works. i'm not sure though.

my_pup4life wrote:

is there a possible workaround for this:

<this sprite clicked?::sensing>

when this sprite clicked
set [clicked? v] to [true]
wait until < not < mouse down? > >
set [clicked? v] to [false]

Computer_Fizz wrote:

my_pup4life wrote:

is there a possible workaround for this:

<this sprite clicked?::sensing>

there are several different workarounds, but the best one is:

when this sprite clicked
set [clicked? v] to [true]
wait until < not < mouse down? > >
set [clicked? v] to [false]

<<touching [mouse pointer v] ?> and <mouse down?>>

Computer_Fizz wrote:

Operators :: operators hat

< < . . . > xor < . . . > :: operators>

can be recreated with the following code:

< not < < . . . > = < . . . > > >

———————————————————–

 < true :: operators> 

can be recreated with the following code:

 < [1] = [1] > 

———————————————————–

 < false :: operators> 

can be recreated with the following code:

 < [1] > [2] > 

———————————————————–

 ( letters ( start ) through ( end :: variables) of ( string ) :: operators) 

can be recreated with the following code:

set [iterator v] to ( start )
set [result v] to []
repeat ( ( ( end :: variables) - ( start ) ) + ( 1 ) )
set [result v] to ( join ( result ) ( letter ( iterator ) of ( string ) ) )
end

———————————————————–

< ( . . . ) ≥ ( . . . ) :: operators >

can be recreated with the following code:

< not < ( . . . ) < ( . . . ) > >

———————————————————–

< ( . . . ) ≤ ( . . . ) :: operators >

can be recreated with the following code:

< not < ( . . . ) > ( . . . ) > >

LukeManiaStudios wrote:

The thing is with the "letters through of " is that 1: there's a delay. 2 there's only room for 1 calculation at a time. It can work, but for larger projects it isn't a viable workaround. most of these workarounds are great though, and i do use quite a few of them!

if <> forever {

}::control
 
if <> then
forever

end
end

When x=(), y=() ::motion hat

if <<(x position) = []> and <(y position) = []>> then

end

mica43683 wrote:

Computer_Fizz wrote:

my_pup4life wrote:

is there a possible workaround for this:

<this sprite clicked?::sensing>

there are several different workarounds, but the best one is:

when this sprite clicked
set [clicked? v] to [true]
wait until < not < mouse down? > >
set [clicked? v] to [false]

Well, no. That would mean you can remove the mouse from the sprite with a drag and it would still consider it clicked. You kinda have a habit of complicating things with variables and whatnot. The best one is, actually,

<<touching [mouse pointer v] ?> and <mouse down?>>

because it remains as a boolean and doesn't require too much extra work and clutter of the variable list, which was the original suggestion.

stamp at [ v]::pen

go to [ v]
stamp

forever wait::control

wait until <put nothing in here>::control

no8pupil wrote:

forever wait::control

wait until <put nothing in here>::control

wait [Infinity] secs

stop [this script v]

<variable has ()?::variables>

<(any var) = [x]> //'x' is the what the variable has

<<>≠<>::operators>

<not <<>=<>>

no8pupil wrote:

<variable has ()?::variables>

<(any var) = [x]> //'x' is the what the variable has

<<>≠<>::operators>

<not <<>=<>>

no8pupil wrote:

<variable has ()?::variables>

<(any var) = [x]> //'x' is the what the variable has

<<>≠<>::operators>

<not <<>=<>>

define does (variable) have (text)
set [counter v] to [1]
set [counter_2 v] to [1]
set [finished word v] to []
repeat (length of (variable))
if <(letter (counter) of (variable)) = (letter (counter) of (text))> then 
set [finished word v] to (join (finished word) (letter (counter_2) of (text))
change [counter_2 v] by [1]
if <(finished word) = (text)> then 
set [yes/no v] to [yes]
else
set [yes/no v] to [no]
end
else
if <(yes/no) = [no]> then
set [current word v] to []
set [counter_2 v] to [1]
end
end
change [counter v] by [1]
end

PixelYoshi wrote:

no8pupil wrote:

<variable has ()?::variables>

<(any var) = [x]> //'x' is the what the variable has

<<>≠<>::operators>

<not <<>=<>>

actually, that doesn't work. that only tells you the variable has () if it contains ONLY the value your looking for. heres a way to do it thats works the way you want it to:

define does (variable) have (text)
set [counter v] to [1]
set [counter_2 v] to [1]
set [finished word v] to []
repeat (length of (variable))
if <(letter (counter) of (variable)) = (letter (counter) of (text))> then 
set [finished word v] to (join (finished word) (letter (counter_2) of (text))
change [counter_2 v] by [1]
if <(finished word) = (text)> then 
set [yes/no v] to [yes]
else
set [yes/no v] to [no]
end
else
if <(yes/no) = [no]> then
set [current word v] to []
set [counter_2 v] to [1]
end
end
change [counter v] by [1]
end

whether its in the variable or not is shown by the yes/no variable. the only thing is its not a boolean block but that just doesn't work.

(var) contains [x] ? :: #5EC15D

Computer_Fizz wrote:

mica43683 wrote:

Computer_Fizz wrote:

my_pup4life wrote:

is there a possible workaround for this:

<this sprite clicked?::sensing>

there are several different workarounds, but the best one is:

when this sprite clicked
set [clicked? v] to [true]
wait until < not < mouse down? > >
set [clicked? v] to [false]

Well, no. That would mean you can remove the mouse from the sprite with a drag and it would still consider it clicked. You kinda have a habit of complicating things with variables and whatnot. The best one is, actually,

<<touching [mouse pointer v] ?> and <mouse down?>>

because it remains as a boolean and doesn't require too much extra work and clutter of the variable list, which was the original suggestion.

No, because then you can put the mouse down first, then touch the sprite. Which is why I said “there are several different workarounds, but the best one is:”, and then the closest workaround. More functionality is not “complicating”.

<<touching [mouse pointer v] ?> and <mouse down?>>

DipLeChip wrote:

PixelYoshi wrote:

no8pupil wrote:

-snip-

or

(var) contains [x] ? :: operators

Yeah, how was this operator missed?

Computer_Fizz wrote:

while < . . . > {
    . . .
} @loopArrow :: control

can be recreated with the following code:

repeat until < not < . . . > >
    . . .
end

 while < . . . > {} @loopArrow :: control 

Please don't count this as advertising — I'm only trying to give an example and you can
use these hacked blocks without credit. They all work in 3.0.
https://scratch.mit.edu/projects/315757409/
Includes:

    while <> {
    } @loopArrow :: control
    
    for each [var v] in [10] {
    } :: control
    
    all at once {
    } :: control
    
    (counter :: control)
    clear counter :: control
    increment counter :: control
    
    <loud? :: sensing>
    

Shuffle the[list v] :: list

repeat until<(length of[temp v])\>[2]>
add[0]to[temp v]
end
replace item[1]of[temp v]with(pick random[1]to[2147483646])
replace item[2]of[temp v]with(length of[list v])
repeat((length of[list v])-[1])
replace item[1]of[temp v]with(([48271]*(item[1]of[temp v]))mod[2147483647])
replace item[3]of[temp v]with(item(((item[1]of[temp v])mod(item[2]of[temp v]))+[1])of[list v])
replace item(((item[1]of[temp v])mod(item[2]of[temp v]))+[1])of[list v]with(item(item[2]of[temp v])of[list v])
replace item(item[2]of[temp v])of[list v]with(item[3]of[temp v])
replace item[2]of[temp v]with((item[2]of[temp v])-[1])
end

DipLeChip wrote:

PixelYoshi wrote:

no8pupil wrote:

<variable has ()?::variables>

<(any var) = [x]> //'x' is the what the variable has

<<>≠<>::operators>

<not <<>=<>>

actually, that doesn't work. that only tells you the variable has () if it contains ONLY the value your looking for. heres a way to do it thats works the way you want it to:

define does (variable) have (text)
set [counter v] to [1]
set [counter_2 v] to [1]
set [finished word v] to []
repeat (length of (variable))
if <(letter (counter) of (variable)) = (letter (counter) of (text))> then 
set [finished word v] to (join (finished word) (letter (counter_2) of (text))
change [counter_2 v] by [1]
if <(finished word) = (text)> then 
set [yes/no v] to [yes]
else
set [yes/no v] to [no]
end
else
if <(yes/no) = [no]> then
set [current word v] to []
set [counter_2 v] to [1]
end
end
change [counter v] by [1]
end

whether its in the variable or not is shown by the yes/no variable. the only thing is its not a boolean block but that just doesn't work.

or

(var) contains [x] ? :: #5EC15D

In [list v], perform a swap on index [] and [] ::list

swap[][]
define swap[a][b]
dual-write(a)(b)(item[b]of[list v])(item[a]of[list v])
define dual-write[a][b][c][d]
replace item(a)of[list v]with(c)
replace item(b)of[list v]with(d)