I've been trying to make it so a script would subtract a date in the past from the current date using the current date block but couldn't find out how. Is it even possible to make a script that does that? Thanks in advance.

You could do this…

((days since 2000) - (# of days between January 1st, 2000 and the date you want))

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███     ███   ██   ████   ██   ███     ███
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-ShadowOfTheFuture- wrote:

You could do this…

((days since 2000) - (# of days between January 1st, 2000 and the date you want))

Could you elaborate on the part with the variables? I'm not understanding why there's a comma and the “and” part near the end.

Never mind I think I made something similar that might work

Actually I don't. Is there any way you could help?

define days since year (year) day of year (day)
set [return v] to (round((days since 2000)+((730000)-(((365)*(year))+(day)))))

Examples of use:

days since year (2018) day of year (1) ::custom

would show the days since January first, 2018 while

days since year (2018) day of year (357)::custom

would show the number of days since the date of me writing this post.
In case you can't see the order of the scratchblocks, here's the equation:
round((days since 2000)+((730000)-(((365)*(year))+(day))))

This is essentially just an automated version of what -ShadowOfTheFuture- said.

Apparently my old signature was lost::custom hat
Oh well, I guess this will do ::custom cap

-ShadowOfTheFuture- wrote:

You could do this…

((days since 2000) - (# of days between January 1st, 2000 and the date you want))

((days since 2000) - (days between NYD *2000 and date of your choosing))

*2000 was a leap year, and so was 2004, 2008, etc.
Use https://planetcalc.com/274/

if <[asking for help] = [true]> then
say [please link your project]
end