This one's a little easier than the last one

$(".box-head")[0].textContent = "committing AT crimes since $whenever"

Now that's interesting. I'll try this out.

btw all of the numbers are base 10, in case that wasn't clear. if you need them in hexadecimal, use the python
there are additionally 2 `sPecIal numbers` that went into making this challenge (neither are prime). bonus cookie for anyone who gets them. you'll know when you find them

$(".box-head")[0].textContent = "committing AT crimes since $whenever"

MegaApuTurkUltra wrote:

btw all of the numbers are base 10, in case that wasn't clear. if you need them in hexadecimal, use the python

hex(<number>)

there are additionally 2 `sPecIal numbers` that went into making this challenge (neither are prime). bonus cookie for anyone who gets them. you'll know when you find them

Okay, then.

MegaApuTurkUltra wrote:

hint

yes i figured out that part already. i'm trying to figure out how you can decrypt something with an encryption key and no decryption key

xn--cr8h wrote:

yes i figured out that part already. i'm trying to figure out how you can decrypt something with an encryption key and no decryption key

HMMMMmmmmmmmmmm

just find the decryption key

$(".box-head")[0].textContent = "committing AT crimes since $whenever"

What is the fundamental computational problem that gives RSA its security? How do you derive the parameters for a particular RSA round?

$(".box-head")[0].textContent = "committing AT crimes since $whenever"

It's a small composite number. In theory, one could probably factorise it or something.

haha yes

nataIia wrote:

haha yes

nice job xd

$(".box-head")[0].textContent = "committing AT crimes since $whenever"

Reference solution:



Explanation:

RSA security depends on not being able to factor very large numbers. If you can get the factors of n, you can decrypt the message. Now my n here may look like a big number, but remember that computers are way faster than humans. Usually RSA keys are 2048 or 4096 bits long. This is 86 bits. My machine factored it in 0.0612 seconds.

Once we have p and q, the factors of n, we calculate the decryption key d with

Then decrypt

$(".box-head")[0].textContent = "committing AT crimes since $whenever"

Cute