The name says it all.
Could be useful in some situations.

when I receive [randomize list v]
randomize items in [list a v] ::list

Try this for picking random songs in a list:

when green flag clicked
delete (all v) of [list a v]
add [song1] to [list a v]
add [song2] to [list a v]
add [song3] to [list a v]
play sound (item (random v) of [list a v] :: list)

if you name all the sounds/songs “song1” “song2” and “song3” then it will play the selected one.

Try this for just picking a random item in said list:

when green flag clicked
delete (all v) of [list b v]
add [random1] to [list b v]
add [random2] to [list b v]
add [random3] to [list b v]
set [Random item v] to (item (random v) of [list b v] :: list) 

If you want to have the whole list randomized for later, you can use the script below:

set [counter v] to (0)
repeat (length of [list v] :: list)
change [counter v] by (1)
insert (item (counter) of [list v] :: list) at (pick random (1) to (counter)) of [list v]
delete ((counter) + (1)) of [list v]
end

This works by placing each item in the list in a random position relative to the rest of the previously randomized items. Example of a single repeat stage: items 1, 2, and 3 of a five element list have been randomized; item 4 is then moved at one of the following positions: before 1, after 1 and before 2, after 2 and before 3, or after 3.

ACE009 wrote:

If you want to have the whole list randomized for later, you can use the script below:

set [counter v] to (0)
repeat (length of [list v] :: list)
change [counter v] by (1)
insert (item (counter) of [list v] :: list) at (pick random (1) to (counter)) of [list v]
delete ((counter) + (1)) of [list v]
end

Ooh neat.

repeat (10)
add (pick random (1) to (10)) to [list v]
end

Now there are random numbers in the list.

GullumIncComicz wrote:

repeat (10)
add (pick random (1) to (10)) to [list v]
end

Now there are random numbers in the list.

The suggestion is to be able to take an existing list and randomize the order of the items in it.

Curse you, 60-second rule…

-ShadowOfTheFuture- wrote:

GullumIncComicz wrote:

repeat (10)
add (pick random (1) to (10)) to [list v]
end

Now there are random numbers in the list.

The suggestion is to be able to take an existing list and randomize the order of the items in it.

Curse you, 60-second rule…

Which my workaround does with only one extra variable. Anyway, if you were to use hacked blocks, you can have a custom block take a list dropdown input and then put the var for that in the list blocks.

ACE009 wrote:

If you want to have the whole list randomized for later, you can use the script below:

set [counter v] to (0)
repeat (length of [list v] :: list)
change [counter v] by (1)
insert (item (counter) of [list v] :: list) at (pick random (1) to (counter)) of [list v]
delete ((counter) + (1)) of [list v]
end

This works by placing each item in the list in a random position relative to the rest of the previously randomized items. Example of a single repeat stage: items 1, 2, and 3 of a five element list have been randomized; item 4 is then moved at one of the following positions: before 1, after 1 and before 2, after 2 and before 3, or after 3.

Thanks so much, this makes card games so much easier!