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- lolguy416859
-
Scratcher
5 posts
A New Block Idea!
([ v] Appears in list x times:: list)
Thats The Concept, To Detect How Many Times A Certian Thing Is In A List, Ex: If You Have 1, 1 And 2 On A List, Ill Detect If There Are 2 Ones, If There Are, Remove Them And Put A 2, Same For 2 As Well
( I Know The Name I Gave It Isnt That Good, You Can Name It Whatever You Want If Anyone Even Sees This)
Last edited by lolguy416859 (Oct. 21, 2017 05:12:40)
- DaEpikDude
-
Scratcher
1000+ posts
A New Block Idea!
So you mean
I'll say semi-support for now. wow this is my first semi-support in forever
(amount of [item] in [list v]::list)Yeah, it seems simple enough, but are there really that many times where it's useful?
I'll say semi-support for now. wow this is my first semi-support in forever
And all the world over, each nation's the same,
They've simply no notion of playing the game.
They argue with umpires, they cheer when they've won,
And they practice beforehand, which ruins the fun!
- njb14
-
Scratcher
100+ posts
A New Block Idea!
There's probably a workaround, but a single block would be a lot easier… semi-support, because as DaEpikDude said, there aren't many times where you'd use it.
he/him ♕ art student ♕ scottish
- Charles12310
-
Scratcher
1000+ posts
A New Block Idea!
I'm sure this would be useful.
Or you can do something like this:
Or you can do something like this:
define find number of (string) from list (list)
set [item v] to [0]
set [count v] to [0]
repeat (length of (list) :: list )
change [item v] by (1)
if <(item (item) of (list)) = (string)> then
change [count v] by (1)
end
end
Last edited by Charles12310 (Oct. 21, 2017 16:21:03)
A few internet communication companies want to corrupt the internet by getting rid of net neutrality. Stop Them!
- lolguy416859
-
Scratcher
5 posts
A New Block Idea!
I'm sure this would be useful.
Or you can do something like this:define find number of (string) from list (list)
set [item v] to [0]
set [count v] to [0]
repeat (length of (list) :: list )
change [item v] by (1)
if <(item (item) of (list)) = (string)> then
change [count v] by (1)
end
end
Thanks for a workaround, though it would be cool as a regular block, thanks though
Last edited by lolguy416859 (Oct. 21, 2017 19:38:46)
- lolguy416859
-
Scratcher
5 posts
A New Block Idea!
So you meanYeah, that's a better name for it, I guess your right about about usefulness though, I was thinking for a crafting system, like, if “wood” is in a list at least 3 times, remove them and add “door” to a list(amount of [item] in [list v]::list)Yeah, it seems simple enough, but are there really that many times where it's useful?
I'll say semi-support for now. wow this is my first semi-support in forever
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