Discuss Scratch

artemvideoscratch
Scratcher
24 posts

Can you decode this? (3.5) {LEADERBOARD FINALLY AVAILABLE}

Cipher: ༽遄䮣丁༽䮣靆뫞遄脇䮣༽䮣丁뫞靆脇カU䮣カ༽遄丁脇遄丁遄
Description/hint: A text that's encrypted using Python 3.
Here are the first 4 lines, with the fourth line cut off.
should be replaced with a null char.
def encrypt(plaintext,keytext):
text = plaintext
for key in :
step1 = “”.join([chr(((ord(character) * k

Last edited by artemvideoscratch (Oct. 13, 2025 17:57:28)

BigNate469
Scratcher
1000+ posts

Can you decode this? (3.5) {LEADERBOARD FINALLY AVAILABLE}

Cipher: Lynnq
Description/hint: Squares.

Manually encoded (which is why it's so short), so expect some errors.

If you solve this, please post the method by which you solved it due the high frequency of the word I encoded.

I guess the topic should be revived at some point, right?
MonkeyBean2
Scratcher
500+ posts

Can you decode this? (3.5) {LEADERBOARD FINALLY AVAILABLE}

Cipher:
㤱ⓁⓁ㤱Ѐ㤱〡㕹Ѐ㎩〡ⶐ㙤⟙✐Ѐ⬑㒐
Description/hint: Squares.
davidtheplatform
Scratcher
500+ posts

Can you decode this? (3.5) {LEADERBOARD FINALLY AVAILABLE}

MonkeyBean2 wrote:

Cipher:
㤱ⓁⓁ㤱Ѐ㤱〡㕹Ѐ㎩〡ⶐ㙤⟙✐Ѐ⬑㒐
Description/hint: Squares.
Plaintext: [yaay you solved it]
Solution: [convert each character to decimal, take the square root, convert back to ascii]
I tried this method with bignate469's cipher but it doesn't work, I'm guessing you did too?
nembence
Scratcher
500+ posts

Can you decode this? (3.5) {LEADERBOARD FINALLY AVAILABLE}

BigNate469 wrote:

Cipher: Lynnq
Description/hint: Squares.

Manually encoded (which is why it's so short), so expect some errors.

If you solve this, please post the method by which you solved it due the high frequency of the word I encoded.

I guess the topic should be revived at some point, right?
Plaintext: [Hello]
Solution: [For each letter, get it's index in the English alphabet (A=1, Z=26), find the numbers whose squares are that index modulo 26, then get the letters at that index in the alphabet.]
JS code: [[..."Lynnq"].map(x=>parseInt(x,36)-9).map(x=>{var arr=[]; for(let i=0; i<26; i++) {if(i*i%26==x%26)arr.push(i);} return arr.map(x=>(x+9).toString(36));})]
nembence
Scratcher
500+ posts

Can you decode this? (3.5) {LEADERBOARD FINALLY AVAILABLE}

Cipher: (#9)
  ┌─────┐     ┌─┐     ┌─────┐  
│ ┌─┐ │ ┌───┼─┼───┐ │ ┌─┐ │
┌─┼─┘ │ │ └─┐ │ └─┐ │ └─┼─┘ └─┐
│ │ ┌─┘ │ ┌─┘ │ ┌─┘ │ ┌─┼─┐ ┌─┘
│ └─┘ │ └─┐ └─┘ │ └─┼─┘ └─┐
│ ┌─┐ │ ┌─┘ ┌─┐ │ ┌─┘ ┌─┘
└─┐ │ └─┼─┼───┼─┼───┘ └───┐ │
└─┘ └─┘ └─┘ └─┘
Description: It's a graphical encoding, I encrypted it by hand on a square grid
Hint: 3x5
(if the box drawing characters don't line up in the cipher, try using a different monospace font)
Goldking9
Scratcher
81 posts

Can you decode this? (3.5) {LEADERBOARD FINALLY AVAILABLE}

 60, 59, 58, 59, 58, 59, 58, 57, 58, 57, 59, 58

Hint: This represents music

Last edited by Goldking9 (Oct. 14, 2025 22:52:06)

Goldking9
Scratcher
81 posts

Can you decode this? (3.5) {LEADERBOARD FINALLY AVAILABLE}

Oops.

Last edited by Goldking9 (Oct. 14, 2025 22:51:42)

kRxZy_kRxZy
Scratcher
1000+ posts

Can you decode this? (3.5) {LEADERBOARD FINALLY AVAILABLE}

Goldking9 wrote:

 60, 59, 58, 59, 58, 59, 58, 57, 58, 57, 59, 58

Hint: This represents music
PlainText:[ C B A# B A# B A# A A# A B A#]
Solution: [These are MIDI notes, so just learn music and you'll know]

I swear this is jingle bells

Last edited by kRxZy_kRxZy (Oct. 15, 2025 17:28:13)

IDidAFard
Scratcher
4 posts

Can you decode this? (3.5) {LEADERBOARD FINALLY AVAILABLE}

Cipher:
䍋餉͉Λ⬩ϋ箩͛獻뤃䍻뤃ፋꎙλ箓夁튃㭻笡ͻ焃쭻꤃㍻鄃⌫᭻⍋猹Σ
Hint: 285

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