New Block to act like a break statement

Catzcute4

Kazomix wrote:
have you forgotten scratch is full of work-aroundable things?

Yes, but technically, basically all of scratch is work-around able. In fact, technically we wouldn’t need addition and multiplication: just use the inverses or make your own virtual machine. However, that’s just not ever practical. This is why “there’s a work around” is not valid. Look at this: Say you want a loop to go 50 times or stop if a condition is met while it’s running. Currently you have to do this:

set [i v] to (0)
repeat until <<(i)=(50)> or <condition :: grey > :: operator {
change [i v] by (1)
…
end

But with this block you could do this:

repeat (50) :: control{
…
if <condition :: grey > then :: control {
stop [this loop v] :: control
end
end

Which way do you think is more readable: the first one, or the second one? I think the second one is more readable, because it explicitly tells us that we’re looping 50 times, but we stop if there’s a certain condition met. Plus, it’s way more clear we’re repeating if we aren’t using a helper variable, and if we do use the variable, it’s way more bulkey. Readability is also important in coding. Not only that, but option 2 also tells the reader that we’re specifically stopping the loop when a condition occurs, which is far less obvious in option 1.

Last edited by Catzcute4 (March 20, 2024 21:56:49)

Catzcute4

gdfsgdfsgdfg wrote:
Maybe this is better
forever {
stop [this loop v]
} :: control :: loop
when you put a stop [ v] block
in the forever loop then this option is available

That’s when you use repeat until. It’s less weird in that case.

Last edited by Catzcute4 (Feb. 16, 2024 23:29:28)

BringUpYourPost

uh –>

stop [ this script v]

Malicondi

BringUpYourPost wrote:
uh –>
stop [ this script v]

That stops the entire script, including scripts after the loop that you may want to be run, although there is a workaround i think this would be a incredibly helpful solution (seeing as i use this all the time in python and java)
support

medians

Bringing this topic up.

starlightsparker

MegaApuTurkUltra wrote:

Support but there is a workaround. Put your loop in a custom block and then do

define DoLoop
set [i v] to [0]
repeat (length of [list v])
    if <(item (i) of [list v]) = [John]> then
        stop [this script v]
    end
change [i v] by [1]
end

when gf clicked
DoLoop
say (i) // shows the index of John in list

I’m pretty sure that stops the entire script of the Sprite including code blocks outside that one block

-cloudcoding-

Support, I have looked for this block when starting scratch and just couldn't find it.

starlightsparker

Can’t you use this?

repeat until <(variable) = [value]>
…

end

Malicondi

starlightsparker wrote:
Can’t you use this?
repeat until <(variable) = [value]>
…

end

it would be

repeat until <<(variable) = [value]> or <(runs) = [how many repeats]>>
...
change [runs v] by (1)

but a break loop would be so much simpler and easier to use

Catzcute4

Malicondi wrote:
starlightsparker wrote:
Can’t you use this?
repeat until <(variable) = [value]>
…

end
it would be
repeat until <<(variable) = [value]> or <(runs) = [how many repeats]>>
...
change [runs v] by (1)
but a break loop would be so much simpler and easier to use

and it would make clear what you’re doing

-effortIess-

Bump

medians

Bringing this topic up.

Catzcute4

bumpybumpitybump

MagentaDude1359

love it, support

hypercode96

omg yes yes so support

Catzcute4

another reason t use this: basically every real programming language has a break; statement, like js, and even Blockly has it in its demos

medians

Bringing this topic up.

Catzcute4

oh also another thing, it should be mentioned that the stop this script does work as a custom block ender, but only for that. plus it’s kinda confusing that it works

Creator-H

bump

turtleman885

theonlygusti wrote:

set [i v] to [0]
repeat (length of [list v])
    if <(item (i) of [list v]) = [John]> then
        exit this loop :: control cap //I think this should be just exit loop
    end
change [i v] by [1]
end
say (i) // shows the index of John in list

turtleman885 wrote:
SUPPORT!

Last edited by turtleman885 (March 30, 2025 16:05:34)

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