hello, I would like to know if there is a block

(number)  ² ::operators

in scratch?

Ummmmmmmmmmmmmmmm no but you can make it with

()

how can I do it?

To get x^2, just use

(((x)) * ((x)))

If you want to take any power, like x^y, try:

([e^ v] of (((y)) * ([ln v] of ((x))::operators))::operators)

I just wanted to know if there was a block

((number) squared ::operator)

because in this code

([sqrt v] of (((([x v] of [Sprite1 v]) - ([x v] of [Sprite2 v])) * (([x v] of [Sprite1 v]) - ([x v] of [Sprite2 v]))) + ((([y v] of [Sprite1 v]) - ([y v] of [Sprite2 v])) * (([y v] of [Sprite1 v]) - ([y v] of [Sprite2 v]))))::operators)

it's a bit long…

Lu_Li_49 wrote:

I just wanted to know if there was a block

((number) squared ::operator)

because in this code

([sqrt v] of (((([x v] of [Sprite1 v]) - ([x v] of [Sprite2 v])) * (([x v] of [Sprite1 v]) - ([x v] of [Sprite2 v]))) + ((([y v] of [Sprite1 v]) - ([y v] of [Sprite2 v])) * (([y v] of [Sprite1 v]) - ([y v] of [Sprite2 v]))))::operators)

it's a bit long…

you might be able to use the (number) * (number) method to get the squared value and put it in a variable, that way you won't have to use the block so many times

ametrine_ wrote:

Lu_Li_49 wrote:

I just wanted to know if there was a block

((number) squared ::operator)

because in this code

([sqrt v] of (((([x v] of [Sprite1 v]) - ([x v] of [Sprite2 v])) * (([x v] of [Sprite1 v]) - ([x v] of [Sprite2 v]))) + ((([y v] of [Sprite1 v]) - ([y v] of [Sprite2 v])) * (([y v] of [Sprite1 v]) - ([y v] of [Sprite2 v]))))::operators)

it's a bit long…

you might be able to use the (number) * (number) method to get the squared value and put it in a variable, that way you won't have to use the block so many times

Or sth like this to prevent repeating too

define dist between (sprite 1) and (sprite 2)
set [delta x v] to (([x position v] of (sprite 1)) - ([x position v] of (sprite 2))
set [delta y v] to (([y position v] of (sprite 1)) - ([y position v] of (sprite 2))
set [result v] to ([sqrt v] of (((delta x) * (delta x)) + ((delta y) * (delta y)))

I have no idea why there isn't a report block yet, though you could also have:

define square of (number)
set [result v] to ((number) * (number))

Also, there's already a distance to () blocks if you aren't aware, and the x and y should be “x position” and “y position”

ok, thank you.

i can do in 3 blocks

go to [point 1]
set [distance] to (distance to [point2])

why didnt you just that?

THEIMPORTANT wrote:

i can do in 3 blocks

go to [point 1]
set [distance] to (distance to [point2])

why didnt you just that?

Doesn’t work for distance to a point. (An x y position)