Can you decode this? (3.0) (New system in place)

TheCreatorOfUnTV

TheCreatorOfUnTV wrote:
Cipher creator: @TheCreatorOfUnTV
Cipher:
iimpqxrwrf
Difficulty: 2
Short description: Your hint is that this isn't SHA-512

Last edited by TheCreatorOfUnTV (Oct. 18, 2024 21:20:53)

co0lcr34t10ns

Both ciphers added. I think I'm going to go for both of them.

8to16

Cipher Creators: me
Cipher:

|-- |_|_| X |--

Difficulty Level: 1
Short Description: Rotate

No decoins btw

BigNate469

8to16 wrote:
Cipher Creators: me
Cipher:
|-- |_|_| X |--
Difficulty Level: 1
Short Description: Rotate

No decoins btw

“Text”

How: rotate 90 degrees clockwise, read from top to bottom.

8to16

BigNate469 wrote:
“Text”

How: rotate 90 degrees clockwise, read from top to bottom.

correct

KentuckyFriedPlayer

Cipher Creators: me
Cipher:

⡇⡯⡯⡤⠠⡪⡯⡢⠠⠺⠩

Difficulty Level: 2 or 3

Last edited by KentuckyFriedPlayer (Oct. 20, 2024 06:12:08)

co0lcr34t10ns

Woah. The topic got moved to AT without notice. Threw me off. Anyways:

BigNate469 wrote:
8to16 wrote:
Cipher Creators: me
Cipher:
|-- |_|_| X |--
Difficulty Level: 1
Short Description: Rotate

No decoins btw
“Text”

How: rotate 90 degrees clockwise, read from top to bottom.

KentuckyFriedPlayer wrote:
Cipher Creators: me
Cipher:
⡇⡯⡯⡤⠠⡪⡯⡢⠠⠺⠩
Difficulty Level: 2 or 3

Adding

MonkeyBean2

KentuckyFriedPlayer wrote:
Cipher Creators: me
Cipher:
⡇⡯⡯⡤⠠⡪⡯⡢⠠⠺⠩
Difficulty Level: 2 or 3

Cipher Solvers: @MonkeyBean2
Solution:

Good job :)

Code (python):

ciphertext = "⡇⡯⡯⡤⠠⡪⡯⡢⠠⠺⠩"
charset = ''.join([chr(0x2800+n) for n in range(256)])
result = bytes([z.index(j) for j in x])

or simply (subtract start of braille section)

result = bytes([ord(j)-0x2800 for j in x])

Last edited by MonkeyBean2 (Oct. 20, 2024 17:07:47)

8to16

for whatever reason the forum engine didn't care about me using really obscure characters lol

Cipher Creators: microsoft copilot (the script) and me (the text and unicode offset)
Cipher:

࿴ဈဉဓ࿀ဉဓ࿀ဉဍတဏဓဓဉဂဌစ࿁࿁࿁࿁࿀ဈဏဗ࿀ငဉင࿀မဏပ࿀ဓဏဌဖစ࿀ဉန࿟

Difficulty Level: 5
Short Description: Unicode shift

Last edited by 8to16 (Oct. 20, 2024 19:11:11)

co0lcr34t10ns

8to16 wrote:
for whatever reason the forum engine didn't care about me using really obscure characters lol

Cipher Creators: microsoft copilot (the script) and me (the text and unicode offset)
Cipher:
࿴ဈဉဓ࿀ဉဓ࿀ဉဍတဏဓဓဉဂဌစ࿁࿁࿁࿁࿀ဈဏဗ࿀ငဉင࿀မဏပ࿀ဓဏဌဖစ࿀ဉန࿟
Difficulty Level: 5
Short Description: Unicode shift

Add soon. Might be easier than you think

-YourLocalPhantom-

Cipher Creator: -YourLocalPhantom-
Cipher:

s jt ht tnlf afws

Difficulty: 5
Short description: Encoded using an entirely custom cipher (made entirely by myself) that has approximately 3.8184473e+14 possible keys to choose from when encoding messages.

Note: Due to reasons stated above, I don’t think if it’s really fair to post this yet. Should I give a clue of how the cipher works, along with the key so that this is possible to decode?

MonkeyBean2

8to16 wrote:
for whatever reason the forum engine didn't care about me using really obscure characters lol

Cipher Creators: microsoft copilot (the script) and me (the text and unicode offset)
Cipher:
࿴ဈဉဓ࿀ဉဓ࿀ဉဍတဏဓဓဉဂဌစ࿁࿁࿁࿁࿀ဈဏဗ࿀ငဉင࿀မဏပ࿀ဓဏဌဖစ࿀ဉန࿟
Difficulty Level: 5
Short Description: Unicode shift

Cypher Solvers: Me (@MonkeyBean2)
Solution:

This is impossible!!!! how did you solve it?

Code used to solve it (python):

cyphertext = "࿴ဈဉဓ࿀ဉဓ࿀ဉဍတဏဓဓဉဂဌစ࿁࿁࿁࿁࿀ဈဏဗ࿀ငဉင࿀မဏပ࿀ဓဏဌဖစ࿀ဉန࿟"
result = ''.join([chr(ord(b)-4000) for b in cyphertext])

I just looked at the unicode character codes of the string, and tried 4000 as the offset as my first guess (which worked!).
If it hadn't worked, I would have ran the above code in a loop to try out a few thousand offsets, and then manually search through them, or use character frequency analysis on one of them and match that to english letter frequencies.

Last edited by MonkeyBean2 (Oct. 20, 2024 21:24:13)

davidtheplatform

-YourLocalPhantom- wrote:
Cipher Creator: -YourLocalPhantom-
Cipher:
s jt ht tnlf afws
Difficulty: 5
Short description: Encoded using an entirely custom cipher (made entirely by myself) that has approximately 3.8184473e+14 possible keys to choose from when encoding messages.

Note: Due to reasons stated above, I don’t think if it’s really fair to post this yet. Should I give a clue of how the cipher works, along with the key so that this is possible to decode?

I don't think this is a good submission, since there isn't a way for us to decipher it even if we had the key.
Can you post the cipher method? If there's some way to find the key without waiting 10 million years for your computer to guess it, then I think this would be a good submission.

8to16

MonkeyBean2 wrote:
8to16 wrote:
for whatever reason the forum engine didn't care about me using really obscure characters lol

Cipher Creators: microsoft copilot (the script) and me (the text and unicode offset)
Cipher:
࿴ဈဉဓ࿀ဉဓ࿀ဉဍတဏဓဓဉဂဌစ࿁࿁࿁࿁࿀ဈဏဗ࿀ငဉင࿀မဏပ࿀ဓဏဌဖစ࿀ဉန࿟
Difficulty Level: 5
Short Description: Unicode shift
Cypher Solvers: Me (@MonkeyBean2)
Solution:
This is impossible!!!! how did you solve it?
Code used to solve it (python):
cyphertext = "࿴ဈဉဓ࿀ဉဓ࿀ဉဍတဏဓဓဉဂဌစ࿁࿁࿁࿁࿀ဈဏဗ࿀ငဉင࿀မဏပ࿀ဓဏဌဖစ࿀ဉန࿟"
result = ''.join([chr(ord(b)-4000) for b in cyphertext])
I just looked at the unicode character codes of the string, and tried 4000 as the offset as my first guess (which worked!).
If it hadn't worked, I would have ran the above code in a loop to try out a few thousand offsets, and then manually search through them, or use character frequency analysis on one of them and match that to english letter frequencies.

CORRECT

co0lcr34t10ns

-YourLocalPhantom- wrote:
Cipher Creator: -YourLocalPhantom-
Cipher:
s jt ht tnlf afws
Difficulty: 5
Short description: Encoded using an entirely custom cipher (made entirely by myself) that has approximately 3.8184473e+14 possible keys to choose from when encoding messages.

Note: Due to reasons stated above, I don’t think if it’s really fair to post this yet. Should I give a clue of how the cipher works, along with the key so that this is possible to decode?

I'd say yes. This would be impossible to brute force without the luck of a god. I think that the cipher clue should be more upfront than the key, which could be a little cipher in of itself if you want. Even then, you're still greatly reducing the difficulty of the cipher.
Also I'm tired so all edits tomorrow morning. You might not even be awake by then.

Last edited by co0lcr34t10ns (Oct. 20, 2024 23:21:03)

MonkeyBean2

co0lcr34t10ns wrote:
-YourLocalPhantom- wrote:
Cipher Creator: -YourLocalPhantom-
Cipher:
s jt ht tnlf afws
Difficulty: 5
Short description: Encoded using an entirely custom cipher (made entirely by myself) that has approximately 3.8184473e+14 possible keys to choose from when encoding messages.

Note: Due to reasons stated above, I don’t think if it’s really fair to post this yet. Should I give a clue of how the cipher works, along with the key so that this is possible to decode?
I'd say yes. This would be impossible to brute force without the luck of a god. I think that the cipher clue should be more upfront than the key, which could be a little cipher in of itself if you want. Even then, you're still greatly reducing the difficulty of the cipher.
Also I'm tired so all edits tomorrow morning. You might not even be awake by then.

Also, even if someone did bruteforce it (which could take maybe a month for this, heavily dependent on the algorithm used) the main problem would be that the results would include a lot of valid words. A cypher challenge is only a good challenge when the possible input text is constrained enough that it is clear what it is.

co0lcr34t10ns

All changes have been made. HOLY CRAP! MonkeyBean2 is not stopping! They have 12 DeCoins!
Also how has no one solved Cipher #1 yet, it's single layered and uses one website

-YourLocalPhantom-

I'm gonna cancel my cipher for now (the newer one).

MonkeyBean2

Useful tools for creating and solving ciphers:
CyberChef A great tool for playing with ciphers, has tons of operations.
ciphereditor.com a node/graph based cipher pipeline editor thing
cryptii.com pretty much just a simpler version of the above, but using a single chain of operations (so you can't implement certain more complex ciphers).
Overall, CyberChef has the most operations, and allows you to pass multiple non-static arguments to an operation, like ciphereditor (but has many more operations so it is better I guess).
Also, with both CyberChef and ciphereditor you can save your code with a URL to share with other people (this is great for this forum topic, as it makes it very easy to share how you encoded/decoded a cipher challenge)

Last edited by MonkeyBean2 (Oct. 21, 2024 15:09:54)

8to16

Cipher Creators: me
Cipher:

⁹⁼₄ₑ⁄‸₌₀₁₋‸⁻₁₈₀⁽₊‸₏⁹₋‸⁽⁹₌⁽₆‸⁺ₑ‸⁹₆‸⁽₎₁₄‸₃₍₅₉₍⁹₌⁆‸⁚⁽₌₌⁽₊‸₄₍⁻₃‸₆⁽ₐ₌‸₌₁₅⁽

Difficulty Level: 5
Short Description: Clue is in my username

100th post in this topic

Last edited by 8to16 (Oct. 21, 2024 19:48:04)

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