I want to rotate my sprite, but here's the thing: I can't use the rotate block because I'm drawing it with pen so that it can use arbitrary data for the sprite.
How do I do something like this:

with the sprite?

trig, assuming I've understood (which i frequently don't :P)

AHypnoman wrote:

trig, assuming I've understood (which i frequently don't :P)

Great, but that didn't work, it just made the sprite move in a circle around a location (which is not what I'm looking for, I'm looking for the same thing as rotation, but for pen).

TheCreatorOfUnTV wrote:

~snip~
Great, but that didn't work, it just made the sprite move in a circle around a location (which is not what I'm looking for, I'm looking for the same thing as rotation, but for pen).

Could you share your code?

AHypnoman wrote:

TheCreatorOfUnTV wrote:

~snip~
Great, but that didn't work, it just made the sprite move in a circle around a location (which is not what I'm looking for, I'm looking for the same thing as rotation, but for pen).

Could you share your code?

This project has similar code to the one in my project. (I'm not sharing the project because it is an unfinished update to one of my projects)
Anyway, I don't think

AHypnoman wrote:

has an issue itself (besides the 2 extra x positions which I corrected) but I think it's code for the wrong thing. I'm not looking to move the sprite in a circle around a sprite, I'm looking to rotate the sprite like with this block:

but I'm using pen, so I have to do something else, and I need to rotate each pixel to do it.

You could use the script @AHypqnoman provided and apply it to each point's coordinates, if the project you provided is similar enough to what you want.

completeness wrote:

AHypnoman wrote:

trig, assuming I've understood (which i frequently don't :P)

Close, but not correct.

Recall the trig identities: sin(x+y) = sin x cos y + cos x sin y, and cos(x+y) = cos x cos y - sin x sin y. You can easily find a proof for these online.
Thus to rotate, the x position you must go to is:
x * cos(direction) - y * sin(direction),
And the y position is:
x * sin(direction) + y * cos(direction)
Too lazy to type it out in Scratchblocks.

It worked, thank you!

completeness wrote:

AHypnoman wrote:

trig, assuming I've understood (which i frequently don't :P)

Close, but not correct.

Recall the trig identities: sin(x+y) = sin x cos y + cos x sin y, and cos(x+y) = cos x cos y - sin x sin y. You can easily find a proof for these online.
Thus to rotate, the x position you must go to is:
x * cos(direction) - y * sin(direction),
And the y position is:
x * sin(direction) + y * cos(direction)
Too lazy to type it out in Scratchblocks.

Oh I was assuming they wanted what amounted to a ‘move’ block.

As anticipated, I'm wrong :P

I'll report this as resolved