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- qwertycodechamp90411
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Scratcher
100+ posts
Raising number to really large exponent
What would be the most effective way to find 1.55^x, where x could be a number as large as 1 000 000?
Edit: I have a product block that doesn't round, but it stops working effectively (i.e. fast) at > 100 for x.
Edit: I have a product block that doesn't round, but it stops working effectively (i.e. fast) at > 100 for x.
Last edited by qwertycodechamp90411 (Sept. 9, 2023 11:13:12)
- sashimiricedev
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Scratcher
100+ posts
Raising number to really large exponent
You can use scientific notation to raise a number to a large power of ten, but there is not a real 
((b) ^ (e)::operators)block. Sorry

Last edited by sashimiricedev (Sept. 9, 2023 10:19:29)
- qwertycodechamp90411
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Scratcher
100+ posts
Raising number to really large exponent
You can use scientific notation to raise a number to a large power of ten, but there is not a realYeah, I know that, but how do I do it, while avoiding the rounding error?((b) ^ (e)::operators)block. Sorry
- griefercube
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Scratcher
500+ posts
Raising number to really large exponent
1. Why would you need such a huge number?
2. Scratch stores numbers as 32 bits (I think) so rounding errors couldn’t be avoided and might result in answer being infinity.
3. Here’s the method I tested on:
2. Scratch stores numbers as 32 bits (I think) so rounding errors couldn’t be avoided and might result in answer being infinity.
3. Here’s the method I tested on:

- qwertycodechamp90411
-
Scratcher
100+ posts
Raising number to really large exponent
1. Why would you need such a huge number?As I said, I already know that. I'm asking for a way to do this efficiently without the rounding error.
2. Scratch stores numbers as 32 bits (I think) so rounding errors couldn’t be avoided and might result in answer being infinity.
3. Here’s the method I tested on:
- qwertycodechamp90411
-
Scratcher
100+ posts
Raising number to really large exponent
1. Why would you need such a huge number?I need a large number for accurate precision.
2. Scratch stores numbers as 32 bits (I think) so rounding errors couldn’t be avoided and might result in answer being infinity.
3. Here’s the method I tested on:
- griefercube
-
Scratcher
500+ posts
Raising number to really large exponent
Unfortunately as I beforehand mentioned, scratch will inevitably round the number as it uses 32 bits (32 digits) to store numbers, meaning that a number cannot exceed 10^309, or else it will display Infinity.
- qwertycodechamp90411
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Scratcher
100+ posts
Raising number to really large exponent
Unfortunately as I beforehand mentioned, scratch will inevitably round the number as it uses 32 bits (32 digits) to store numbers, meaning that a number cannot exceed 10^309, or else it will display Infinity.Except if you don't use math blocks, which is what I did. My problem is that it is slower than a snail with slowness 99999 if x > 1000
- qwertycodechamp90411
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Scratcher
100+ posts
Raising number to really large exponent
I'll try to make it more effective tomorrow.
I've never had a problem with the 60 second rule before. I feel the pain now.
I've never had a problem with the 60 second rule before. I feel the pain now.
- qwertycodechamp90411
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Scratcher
100+ posts
Raising number to really large exponent
Did you find a solution?No, but I think it’s fine.
- awesome-llama
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Scratcher
1000+ posts
Raising number to really large exponent
Scratch stores numbers as 32 bits (I think)
Floats are 32-bit but Scratch and JavaScript use double floats which are double the size, so 64 bits.
https://en.wikipedia.org/wiki/Double-precision_floating-point_format
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