I do I pick a item from a list using a number from 1 to 8

-R4x-

The list isn’t always gonna have the same amount of items

ItsMarlowTime

I think this operator should work for what you are asking

(pick random (1) to (length of [List v] :: list))

-R4x-

ItsMarlowTime wrote:
I think this operator should work for what you are asking
(pick random (1) to (length of [List v] :: list))

That’s not what I meant. This one it just random but I want to chose a item from a list by using a number from 1 to 8

Jman1111

How does your list behave?
Is there a reason you can't just do this?

(item ( num ) of [list v] :: list)

Terry_Epic_Boi

(item ( (pick random (1) to (8))) of [list v] :: list)

Im_KookiereeSoHI

-R4x- wrote:
The list isn’t always gonna have the same amount of items

Do

(pick random [insert number here] to [insert number here])

or

(pick random[insert number here] to (length of [list name here v] :: list))

medians

Copy and paste random into the dropdown, use the above method, or upload a project from 1.x or 2.0 with the item random block/backpack the block:

The 1st or 3rd works if you want to randomize through all items of the list.

-R4x- wrote:
ItsMarlowTime wrote:
I think this operator should work for what you are asking
(pick random (1) to (length of [List v] :: list))
That’s not what I meant. This one it just random but I want to chose a item from a list by using a number from 1 to 8

I'm confused what you mean by this. Do you mean from a variable or something?

Or do you mean like choosing a certain list item based on the value of the number (like 1 would be item 2, 2 would be item 1 or something like that?)
When first seeing the topic, people will believe that you mean as the function of the random item block from before 3.0.

Last edited by medians (March 10, 2023 03:10:43)

-R4x-

Im_KookiereeSoHI wrote:
-R4x- wrote:
The list isn’t always gonna have the same amount of items
Do
(pick random [insert number here] to [insert number here])
or
(pick random[insert number here] to (length of [list name here v] :: list))

It’s also gonna be higher than 8

-R4x-

medians wrote:
Copy and paste random into the dropdown, use the above method, or upload a project from 1.x or 2.0 with the item random block/backpack the block:

The 1st or 3rd works if you want to randomize through all items of the list.
-R4x- wrote:
ItsMarlowTime wrote:
I think this operator should work for what you are asking
(pick random (1) to (length of [List v] :: list))
That’s not what I meant. This one it just random but I want to chose a item from a list by using a number from 1 to 8
I'm confused what you mean by this. Do you mean from a variable or something?

Or do you mean like choosing a certain list item based on the value of the number (like 1 would be item 2, 2 would be item 1 or something like that?)
When first seeing the topic, people will believe that you mean as the function of the random item block from before 3.0.

I want all 8 clones to use their ID to pick their unique number from the list, like I range from 1 to 8 turns into a range from 1 to the length of the list

Last edited by -R4x- (March 10, 2023 03:28:19)

Spentine

-R4x- wrote:
I want all 8 clones to use their ID to pick their unique number from the list, like I range from 1 to 8 turns into a range from 1 to the length of the list

Why 8?
Isn't the length of the list going to be 8? (to match the number of clones)
Why do you want to map a range from 1 to 8 to the length of the list?
What are you even making?

Last edited by Spentine (March 10, 2023 03:33:37)

medians

-R4x- wrote:
I want all 8 clones to use their ID to pick their unique number from the list, like I range from 1 to 8 turns into a range from 1 to the length of the list

If I understand correctly, you can use a cloneid script for this:

Then use this:

You can use an if statement to exclude the main sprite by checking if “cloneid” is 0.

Last edited by medians (March 10, 2023 04:04:11)

-MasterMath-

Terry_Epic_Boi wrote:

(item ( (pick random (1) to (8))) of [list v] :: list)

@Terry_Epic_Boi did it right.

Discuss Scratch