program to find second largest number in a list
anyone knows how to make this code in scratch

when gf clicked
set [largest number v] to [-Infinity]
set [second largest number v] to [-Infinity]
set [index v] to (0)
repeat (length of [list v])
change [index v] by (1)
if <not <(item (index) of [list v]) < (largest number)>> then
set [second largest number v] to [largest number v]
set [largest number v] to (item (index) of [list v])
else
if <(item (index) of [list v]) > (second largest number)> then
set [second largest number v] to (item (index) of [list v]

This is untested because I'm on mobile, but in theory it should work.

examples:
3, 2, 1 will return 2
4, 4, 8 will return 4
1 will return -Infinity

Hope this helps!

Do you mean something like this?

Just copies over everything from the list so you can delete it if you want to save the original list. Then it repeats finding the max until the length is 2 and removes the index that is the largest. And then takes the last element, which will be the 2nd largest num

Thank You