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- anqelxx
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100+ posts
What does "Abs of __" Do in Operators
Hii!
I was wondering what does that block do |
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I was wondering what does that block do |
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([ abs] of ())In Operators ?
Last edited by anqelxx (Aug. 3, 2021 17:33:50)
- A____username
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100+ posts
What does "Abs of __" Do in Operators
It reports the absolute value of the input. The absolute value of a number is it's distance from 0. A simpler way to describe an absolute value is that it makes any number positive. If it is negative, it becomes positive, and if it is positive, it stays the same.
- Lirey
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100+ posts
What does "Abs of __" Do in Operators
Basically it makes any number you give it an even number. Here is an in depth explanation, abs stands for Absolute Value and the absolute value of something is the distance to 0. So the absolute value of -2 would be 2. The abs of 90 would be 90, so on so forth. I hope I answered your question!
- 1492864
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500+ posts
What does "Abs of __" Do in Operators
It reports the distance the number is from 0.
Like:
Like:
([abs v] of (-10)) //Reports 10
([abs v] of (100)) //Reports 100
([abs v] of (0)) //Reports 0
- Yusei-Fudo
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1000+ posts
What does "Abs of __" Do in Operators
Basically it makes any number you give it an even number.
Not true. It works with any number, even odds. It doesn't work to make an odd, even, it makes negative numbers positive.
- Lirey
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100+ posts
What does "Abs of __" Do in Operators
Whoops my bad, that was a typo. I meant to say a positive number. Thanks for catching thatBasically it makes any number you give it an even number.
Not true. It works with any number, even odds. It doesn't work to make an odd, even, it makes negative numbers positive.

- The_Imaginarium
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1000+ posts
What does "Abs of __" Do in Operators
It is a number's magnitude.
- Raymond852
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71 posts
What does "Abs of __" Do in Operators
It reports a number's distance from 0. Since distance can never be negative it reports any number as positive
1 = 1
-1 = 1
0 = 0
If you want to have an inverse
1 = 1
-1 = 1
0 = 0
If you want to have an inverse
([abs v] of (9))you can do
((0) - ([abs v] of ( )))
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