variable that measures position change in pixels for a given sprite from this frame to the last? might be useful. there isn't an obvious workaround for this afaik

Maybe something like this?

(position change of [Sprite1 v] in last [1] seconds::sensing)

and it could be used like

add (position change of [Sprite1 v] in last [1] seconds::sensing) to [list v]

I feel like it would look more like this:

(distance to [last position v])

OP said it would check from the last frame.

-gr wrote:

Maybe something like this?

(position change of [Sprite1 v] in last [1] seconds::sensing)

and it could be used like

add (position change of [Sprite1 v] in last [1] seconds::sensing) to [list v]

Yea this is more what I was envisioning. Ty

you could easily do this by storing the x and y positions of the sprite and the amount of time that passed. speed = distance/time

add (x position) to [list v]
add (y position) to [list v]
reset timer
oogly boogly movement stuff :: #7522d7
add (x position) to [list v]
add (y position) to [list v]
set [time v] to (timer)
set [x speed v] to (((item (3 v) of [list v] :: list) - (item (1 v) of [list v] :: list)) / (time))
set [y speed v] to (((item (4 v) of [list v] :: list) - (item (2 v) of [list v] :: list)) / (time))

idk how to find actual distance though. someone else might though

jlnilocalsip wrote:

variable that measures position change in pixels for a given sprite from this frame to the last? might be useful. there isn't an obvious workaround for this afaik

easiest workaround:

set [ x] to (x position)
set [ y] to (y position)
do things that change x & y
set [ x] to ((x position) - (x))
set [ y] to ((y position) - (y))

i also think that his is a really situation specific block

jlnilocalsip wrote:

variable that measures position change in pixels for a given sprite from this frame to the last? might be useful. there isn't an obvious workaround for this afaik

easiest workaround:

set [ x] to (x position)
set [ y] to (y position)
do things that change x & y
set [ x] to ((x position) - (x))
set [ y] to ((y position) - (y))

i also think that his is a really situation specific block

-Valtren- wrote:

you could easily do this by storing the x and y positions of the sprite and the amount of time that passed. speed = distance/time

add (x position) to [list v]
add (y position) to [list v]
reset timer
oogly boogly movement stuff :: #7522d7
add (x position) to [list v]
add (y position) to [list v]
set [time v] to (timer)
set [x speed v] to (((item (3 v) of [list v] :: list) - (item (1 v) of [list v] :: list)) / (time))
set [y speed v] to (((item (4 v) of [list v] :: list) - (item (2 v) of [list v] :: list)) / (time))

idk how to find actual distance though. someone else might though

the equation is √(x1-x2)^2+(y1-y2)^2 if youre finding the distance between points (x1, y1) to (x2, y2) in code:

([ sqrt] of (((((x1) - (x2)) * ((x1) - (x2)))) + ((((y1) - (y2)) * ((y1) - (y2)))))

Wow that was. Surprisingly easy to work around. Thanks :3

jlnilocalsip wrote:

variable that measures position change in pixels for a given sprite from this frame to the last? might be useful. there isn't an obvious workaround for this afaik

you mean like changing how long it takes for something to glide?

glide (this is your "speed") secs to x: (scouts moms house) y: (tf2 reference go brrr)

About the workarounds, some of the workarounds could be too advanced for new scratchers so making new blocks would be easier for them.

-Valtren- wrote:

you could easily do this by storing the x and y positions of the sprite and the amount of time that passed. speed = distance/time

add (x position) to [list v]
add (y position) to [list v]
reset timer
oogly boogly movement stuff :: #7522d7
add (x position) to [list v]
add (y position) to [list v]
set [time v] to (timer)
set [x speed v] to (((item (3 v) of [list v] :: list) - (item (1 v) of [list v] :: list)) / (time))
set [y speed v] to (((item (4 v) of [list v] :: list) - (item (2 v) of [list v] :: list)) / (time))

idk how to find actual distance though. someone else might though

I wouldn’t say easily tho