I propose this block

When (a) is a multiple of (b) :: control hat
…

The block works when b divided by a is an integer

do you have an example of when and where this might be used

bobcat0701 wrote:

do you have an example of when and where this might be used

Idk sorry

workaround:

if <not <((A) / (B)) contains (.)? :: operators>> then
end

if A is a multiple of B then it will return true, otherwise it will return false.
here's a screenshot in case the scratchblocks don't look very clear:

-Valtren- wrote:

(#4)
workaround:

if <not <((A) / (B)) contains (.)? :: operators>> then
end

if A is a multiple of B then it will return true, otherwise it will return false.
here's a screenshot in case the scratchblocks don't look very clear:

I think a better workaround would be:

<((A) mod (B)) = [0]>

Workaround is very simple with the modulus method or the more easy to understand division with a point test. Plus hat blocks just suck anyway because you can't control when you choose to sample the result.

I’m closing this tomorrow