Pick Random 1 to 10

Themanhimself115

I may be dumb about this question, but I can't seem to understand the pick random script. I've done some games using it, but can't seem to do the show and hide technique? I've tried ways to add “forever” or not. For people that are willing to help me, I'm using the top code as “When I receive.”

Thank you, Themanhimself115

scratch___user12345

Are you saying you want it to be a 50/50 chance if it hides/shows? if so use this:

when I receive [ message v]
if <[0] = (pick random (0) to (1))> then
show
else
hide
end

xxthepowerful

For example :

when green flag clicked
hide
wait (pick random (1) to (10)) secs
show

You can use the pick random block If for example you want something to hide and then wait a random time between for 1-10 sec and then show.

Themanhimself115

My idea was mostly to make the enemy spawn at one of the four points on the map. Basically, I want it if this random doesn't do the right number, then it would try this random number, but if that number wasn't chosen, then it… etc.

link: https://scratch.mit.edu/projects/681037483/

Just go to the link and go to the enemy sprite and i guess try?

Thanks.

Last edited by Themanhimself115 (May 9, 2022 16:35:37)

deck26

I suspect you're making the common mistake

if <(pick random (1) to (4)) = [1]> then

else
if <(pick random (1) to (4)) = [2]> then

else
if <(pick random (1) to (4)) = [3]> then

end

What you should have is

set [myvar v] to (pick random (1) to (4)) 
if <(myvar) = [1]> then
else
 if <(myvar) = [2]> then
else
 if <(myvar) = [3]> then

The second one only generates one random number which will have a value 1 to 4. The first generates multiple random numbers and hopes it eventually gets a match with no guarantee it will.

Last edited by deck26 (May 9, 2022 17:32:33)

KaaBEL-NOOB

Do you mean choosing one of few starting positions by random index? I would recommend having list with the position values in pairs:
item 1 = x position of first spawnpoint
item 2 = y position of first spawnpoint
3 = x pos. of second
4 = y pos. of second
5 = x…
6 = y etc.
Then pick random block can even use lenght of list so you can easily add or remove new spawn positions. The position choosing script will look like this.

set [index v] to ((pick random (1) to ((length of [spawn pos v] :: list) / (2))) * (2))
set x to (item (index) of [spawn positions v] :: list)
set y to (item ((index) + (1)) of [spawn positions v] :: list)
show

tb361

can someone help me i need when this sprite clicked do random 1 to 10 how do i do it

The_Imaginarium

tb361 wrote:
can someone help me i need when this sprite clicked do random 1 to 10 how do i do it

Please create a new topic instead of posting on an existing one if you need help. But to answer your question, have a “when sprite clicked” event block set a variable to random 1 to 10 and change whatever you need according to that variable. For example,

when this sprite clicked
set [variable v] to (pick random (1) to (10))

12435tryhgefbkudrhhc

How can i use this block, It is very confusing

gsaa_711

if <> then
<(pick random () to (10)) = [1]>
hide
end

after that just arrange the blocks correctly

Last edited by gsaa_711 (April 21, 2024 08:20:09)

_-Wolf-Spirit-_

I'm trying to do something where you use a list and you can put thing on the list when playing, and I need to figure out how to make it choose random 1 to the top number that is on the list.

MrKingofScratch

_-Wolf-Spirit-_ wrote:
I'm trying to do something where you use a list and you can put thing on the list when playing, and I need to figure out how to make it choose random 1 to the top number that is on the list.

(item (pick random (1) to (length of [list v] :: list)) of [list v] :: list)

The length of list block outputs how long the list is, or as you put it “the top number that is on the list.”

jediwolf3

set [ v] to (pick random (1) to (10))

Dagriffpatchfan

say ()

Dagriffpatchfan

when stop flag clicked

bloxyandbrew

deck26 wrote:
I suspect you're making the common mistake
if <(pick random (1) to (4)) = [1]> then

else
if <(pick random (1) to (4)) = [2]> then

else
if <(pick random (1) to (4)) = [3]> then

end 
What you should have is
set [myvar v] to (pick random (1) to (4)) 
if <(myvar) = [1]> then
else
 if <(myvar) = [2]> then
else
 if <(myvar) = [3]> then
The second one only generates one random number which will have a value 1 to 4. The first generates multiple random numbers and hopes it eventually gets a match with no guarantee it will.

what this guy means is that the first one makes the deeper the ifs are, the rarer the chance, the second one always has an even chance for all of them.

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