Gato_Amigo111 wrote:

So, I don't like the scratch variable display box and wanted another alternative.

-ElectronicArts- wrote:

Gato_Amigo111 wrote:

So, I don't like the scratch variable display box and wanted another alternative.

you can create it yourself using text engine

if <(foo) = (1000000)> then
set [foo v] to [1 M]
end

Gato_Amigo111 wrote:

Also, I need a way to simplify numbers. For instance, 1,000,000 would come out as 1 mil. and so on. Does anyone know how to do this?

-ElectronicArts- wrote:

if <(foo) = (1000000)> then
set [foo v] to [1 M]
end

Gato_Amigo111 wrote:

Also, I need a way to simplify numbers. For instance, 1,000,000 would come out as 1 mil. and so on. Does anyone know how to do this?

MagicCrayon9342 wrote:

-ElectronicArts- wrote:

if <(foo) = (1000000)> then
set [foo v] to [1 M]
end

Gato_Amigo111 wrote:

Also, I need a way to simplify numbers. For instance, 1,000,000 would come out as 1 mil. and so on. Does anyone know how to do this?

then he would have to do that for 2 mil, 3 mil manually which isn't efficient I'd know because I have unneccesary amounts of functions for basic tasks.

if <<(length of (foo)) = [7]> or <(length of (foo)) > [7]>> then
set [foo  v] to (join (letter (1) of (foo)) [million])
end

I_LOVE_TO_MAKE_STUFF wrote:

Yep, it would be better to use something like this:

if <<(length of (foo)) = [7]> or <(length of (foo)) > [7]>> then
set [foo  v] to (join (letter (1) of (foo)) [million])
end

or anything in that fashion. Hopefully this helps!

if <<(length of (foo)) = [7]> or <(length of (foo)) > [7]>> then
if <(letter (2) of (foo)) > [0]> then
set [foo v] to (join (foo) (join (.) (letter (2) of (join (foo) [ million])))
else
set [foo v] to (join (letter (1) of (foo)) [ million])
end

Scratch137 wrote:

I_LOVE_TO_MAKE_STUFF wrote:

Yep, it would be better to use something like this:

if <<(length of (foo)) = [7]> or <(length of (foo)) > [7]>> then
set [foo  v] to (join (letter (1) of (foo)) [million])
end

or anything in that fashion. Hopefully this helps!

Also, if you'd like to add a decimal for a bit more detail, then something like this should work:

if <<(length of (foo)) = [7]> or <(length of (foo)) > [7]>> then
if <(letter (2) of (foo)) > [0]> then
set [foo v] to (join (foo) (join (.) (letter (2) of (join (foo) [ million])))
else
set [foo v] to (join (letter (1) of (foo)) [ million])
end

1000000 = 1 million
1500000 = 1.5 million