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- QuantumPixel
-
Scratcher
89 posts
tan 90 and cos 90
In the Scratch editor,
The ratio for tan 90 is also faulty. Because tan in the right triangle is opposite theta / adjacent theta, and if theta is ninety, the third angle (adjacent) would be 0, and you can't divide by 0.
([ tan] of (90))is defined as a very large number. This is not true, as tan 90 is sin90/cos90, which is a singularity.
The ratio for tan 90 is also faulty. Because tan in the right triangle is opposite theta / adjacent theta, and if theta is ninety, the third angle (adjacent) would be 0, and you can't divide by 0.
- mathfreak231
-
Scratcher
1000+ posts
tan 90 and cos 90
As x approaches some odd multiple of 90, tan(x) approaches infinity (or negative infinity from the other side) so it's probably just how Scratch calculates the trig ratios.
- TheLogFather
-
Scratcher
1000+ posts
tan 90 and cos 90
You might want to read this…
http://scratch.mit.edu/discuss/topic/39873/
(In particular, my first reply.)
http://scratch.mit.edu/discuss/topic/39873/
(In particular, my first reply.)
Last edited by TheLogFather (Oct. 1, 2014 02:25:57)
- QuantumPixel
-
Scratcher
89 posts
tan 90 and cos 90
You might want to read this…Ah, I get it. Rounding issue. So tan 90 can be defined, since cos 90 is not exactly 0. Thanks!
http://scratch.mit.edu/discuss/topic/39873/
(In particular, my first reply.)
- DevanWolf
-
Scratcher
100+ posts
tan 90 and cos 90
Correction:([ tan]of(90))
([tan v]of(90))See. You just don't need to add the extra space at the start of “tan”, and just add the dropdown look by adding a “v” near the end of “tan”!
- QuantumPixel
-
Scratcher
89 posts
tan 90 and cos 90
Correction:([ tan]of(90))([tan v]of(90))See. You just don't need to add the extra space at the start of “tan”, and just add the dropdown look by adding a “v” near the end of “tan”!
*necropost* lol. Thank you for teaching me that interesting fact, though.
- Serbian_Developer
-
Scratcher
5 posts
tan 90 and cos 90
In the Scratch editor,([ tan] of (90))is defined as a very large number. This is not true, as tan 90 is sin90/cos90, which is a singularity.
The ratio for tan 90 is also faulty. Because tan in the right triangle is opposite theta / adjacent theta, and if theta is ninety, the third angle (adjacent) would be 0, and you can't divide by 0.
…Hmm…
i Think that if([ tan v] of (90))is not defined as a ‘'very large number’' there would be some cases where we couldn't use this glitch for something else
like idk maybe to count the time spent on to doing something in that project or whatever..
And how (removed by moderator - please keep it polite) could you make a triangle that his adjacent is 0!?
i Don't really get it…
Last edited by Paddle2See (March 19, 2015 00:21:09)
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