define add (number) + (another number)
set [addition v] to (number :: custom) //Guessing these workarounds also dont work with decimals?
change [addition v] by (another number :: custom)

define subtract (number) - (2nd number)
set [subtraction v] to (number :: custom)
change [subtraction v] by (join [-] (2nd number :: custom)

scratchastroLOL wrote:

why only remove the multiplication operator, it's not like the other operators have 0 workarounds.

define add (number) + (another number)
set [addition v] to (number :: custom) //Guessing these workarounds also dont work with decimals?
change [addition v] by (another number :: custom)

define subtract (number) - (2nd number)
set [subtraction v] to (number :: custom)
change [subtraction v] by (join [-] (2nd number :: custom)

broExpIainsTheJoke wrote:

NxNmultiply wrote:

Fixed that. Some people don't know decimals, only hexadecimals.

Hey bros and sisters, broExpIainsTheJoke here to explain the joke. The joke is that you can't even enter a hexadecimal number for the mod operator (because you can't enter an X). Created with the broExplainsTheJoke generator

Harakou wrote:

I doubt we'll officially ban these kind of topics outright, but I do agree that they're generally unconstructive. Even when suggested in good faith, removing a block is just something that we're not likely to do unless it's very obviously superfluous. I don't think it's something that we're likely to only consider because someone suggested it.