(item # of [thing] in [list v] :: list)

Sairam1265 wrote:

Please give me the workaround for this block.

(item # of [thing] in [list v] :: list)

set [index v] to [1]
repeat until <(item (index) of [list v]) = [thing]>
    if <(index) = (length of [list v])> then
        ... // Not present.
    end
    change [index v] by (1)
end

[color v] :: looks reporter

DrKat123 wrote:

The workaround for a for/while oop:

set [i v] to [0 
repeat until <(i) = (45)>
...
change [i v] by (1)
end

repeat (45)
...
end

repeat until <not <... ::gray>>
...
end

go to (variable)

Shaymin524 wrote:

Is there a way of doing the equivalent of:

go to (variable)

This block doesn't do anything currently, even when variable is the name of a sprite.

BumpSign wrote:

Shaymin524 wrote:

Is there a way of doing the equivalent of:

go to (variable)

This block doesn't do anything currently, even when variable is the name of a sprite.

Since a variable's position cannot be changed throughout the course of a project, you could simply find the position of the variable and then input that into the “go to x: y:” block.

Shaymin524 wrote:

I mean going to the sprite with the name specified by the variable.

⌠(a) ::operators
│ x^(b) ::operators
⌡ 0 ::operators

(([10^ v] of (((b)+(1))×([log v] of (a))::operators)::operators)÷((b)+(1)) ::operators)

(derivative of x^(b) at x=(a)::operators)

((b) * ([10^ v] of (((b)-(1))×([log v] of (a))::operators)::operators))

say [im with drkat123's message \/]

staffordboys wrote:

What would be a workaround to spliting a string at every certain character and adds it to a list ? I am working on a version now that goes through every character and if it is the choosen character then it adds the previour word to a list

define split (string) at (char) into list
delete (all v) of [list v]
set [i v] to [1]
set [current word v] to []
repeat (length of (string))
if <(letter (i) of (string)) = (char)> then
add (current word) to [list v]
set [current word v] to []
else
set [current word v] to (join (current word) (letter (i) of (string)))
end
change [i v] by (1)
end
if <not <(letter ((i) - (1)) of (string)) = (char)>> then //if it didn't just add the last word to the list
add (current word) to [list v]
end

forever if <>{
} forever else{
}::control cap

forever
if<>then
else