Could we please have an exponents block? ( ) ^ ( )

Zomboss9001

define (number1)^(number2)
repeat (number2)
set [number1] to ((number) * (number1))
end

Botcho_Otkho

Zomboss9001 wrote:

define (number1)^(number2)
repeat (number2)
set [number] to ((number) * (number1))
end

That only works for positive and non-decimal integers.

Last edited by Botcho_Otkho (April 2, 2018 19:49:36)

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ronsid

Support

(() ^ ()::operators)

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Iditaroid wrote:
RalphMath wrote:
Please, please, please add this as an operator just like +-*/ it's a real limitation when teaching a lot of math concepts not to have exponentiation.
I know this is technically necroposting but you raise a good point! An exponent block would certainly make things easier for teachers working with Scratch!

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Botcho_Otkho

ronsid wrote:
Support
(() ^ ()::operators)

Reasons?

I see now that the circumstances of one's birth are irrelevant. It is what you do with the gift of life that determines who you are. - Mewtwo

hailstone-sequence

Botcho_Otkho wrote:
Shushport! If there is a workaround, it's super-duper-mega long and it's annoying to have a total of 34 blocks for just one reporter.
() ^ ()::operators reporter

Try

Charles12310 wrote:

([10^ v] of ((exponent) * ([log v] of (number) :: operators )) :: operators )

It is only 5 blocks.

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Happysoul05

No support.

Not many scratchers use this.
If they use they will only go to 1,2,3,4,5 but will not try 1.5 or 125.

There is a long workaround and

Charles12310 wrote:

([10^ v] of ((exponent) * ([log v] of (number) :: operators )) :: operators )

USE THIS!

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ACE009

hailstone-sequence wrote:
~snip~
Try
Charles12310 wrote:
([10^ v] of ((exponent) * ([log v] of (number) :: operators )) :: operators )
It is only 5 blocks.

The problem with that is that you can’t get exact results because of the values being cut off mid calculation, resulting in things like 2^6=63.999999999995. Thus, I support.

Last edited by ACE009 (May 30, 2018 11:07:05)

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thelostgames

define (number) to the power of (exponent)
set [num v] to (number)
repeat (exponent)
set [num v] to ((num) * (num))
end

This should work

Last edited by thelostgames (Sept. 15, 2018 00:19:18)

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Botcho_Otkho

thelostgames wrote:

define (number) to the power of (exponent)
set [num v] to (number)
repeat (exponent)
set [num v] to ((num) * (num))
end

This should work

Not when the number ia negative or decimal.

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HappyMohid

<() ^ () = ()>

so hard

if <(1) ^ (1) = (10)>

when <(1) ^(1) = (10)>

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ScratchDiogoh

HappyMohid wrote:

<() ^ () = ()>

so hard

if <(1) ^ (1) = (10)>

when <(1) ^(1) = (10)>

What is hard, too? also make a new topic

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space_elephant

support, though there is a workaround.

define (base)^(exponent)::reporter
if<(base)<[0]>::control
if<((exponent)mod(1))=[0]>::control
if<((exponent)mod(2))=[0]>::control
return([e ^ v]of((exponent)*([ln v]of(()-(base)))))::#000 cap
else
return(()-([e ^ v]of((exponent)*([ln v]of(()-(base))))))::#000 cap
end
else
return[NaN]::#000 cap//it is complex
end
else
return([e ^ v]of((exponent)*([ln v]of(base))))::#000 cap
end

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space_elephant

mitchboy wrote:
kayybee wrote:
The short version works for all real numbers, the long one doesn't.
Actually, 3.14 ^ 3.14 results in 30.959 on my custom block (about seven posts above). Try it. It just doesn't work with negative numbers or fractions. And my project barely involves any heavy scripting or math at all. All you need is:
- three variables
- a repeat block
- a subtraction and a multiplication block
- a set variable block

That's it. It took me like two minutes.

3.14 ^ 3.14 = 36.33783888017471

you got 3.14 ^ 3 = 30.959144000000002

Cyoce wrote:

Support

((0) ^ (0) :: operators)[/quote]

Not a good example. Most languages answer one.

Support suggestion.

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TheGreenFlash

I believe this block would be helpful because it could be used in many projects that use physics simulators, 3D, and other things with a lot of math, there is no easy or efficient workaround, especially when using decimals, and Scratchers who don't know about exponents might play around with and learn about them.
For these reasons, I support and hope that the Scratch Team decides to add the Exponential Operator Block to Scratch.

noogai34

Turn Left (0 ^ 0) radians:: motion

Still thinking about it

Last edited by noogai34 (April 28, 2019 18:53:40)

S U C C

noogai34

define (base) ^ (exponent):: reporter
set [variable v] to (base:: custom - arg)
repeat (exponent:: custom - arg)
change [variable v] by ((base) * (base))
end

No support, the above code is a workaround
But it would still be handy in the education industry!

Last edited by noogai34 (April 28, 2019 21:42:47)

S U C C

imfh

Support, workarounds are less precise and more costly than this could be. It shouldn't be difficult to implement either. The only downside that I could think of is that it might be confusing to some Scratchers or seem too advanced.

noogai34 wrote:
define (base) ^ (exponent):: reporter
set [variable v] to (base:: custom - arg)
repeat (exponent:: custom - arg)
change [variable v] by ((base) * (base))
end
No support, the above code is a workaround
But it would still be handy in the education industry!

That solution works if you only need to work with small powers, but not if you want to do many large ones and quickly. The point of adding it is so there is no need to use a workaround.

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