How can I make variables in base-6?

I was making this game which I didn't want to have text, but I needed numbers. My solution? Make a whole new set of numbers! Because that will work out just fine! These numbers are in base 6 but I can't make my engine show the variable in base-6.

I have thought of one method, but it is abstract and I don't know how to code it. I thought of using two variables, one to show the “true” value, and another to show that value in base 6 which the engine reads and displays numbers accordingly, but I don't know how to do that.

In case you don't know what base-6 is, which is entirely possible keep reading, otherwise, skip everything below the line…
__________________________________________________________________________________________________
It is a system of counting. The system you probably know is base-10.

Base 10 is like this:
1, 2, 3, 4, 5, 6, 7, 8, 9, and now I am out of characters so I put a 1 in the tens place and make 10. From there I go like normal 11, 12, 13…

With base-6, you go like this:
1, 2, 3, 4, 5, 6, 11. What happened there? Well, in base 6 you have only 6 characters, so you do the same thing as base 10 but when you reach six and not ten. so it looks like 1, 2, 3, 4, 5, 6, 10, 11, 12 ,13, 14, 15, 20…

If you need, I've made a little chart showing base 10 with its base 6 equivalents.

1|2|3|4|5|6| 7| 8| 9|10|11|12
1|2|3|4|5|6|10|11|12|13|14|15

Say [Hello World]

What you have put is base 7 not base 6.
Base 6 uses 0-5

Either way, converting from decimal should be do able, let me have a look at it….

set [decimal v] to [600]
set [number base v] to [6]
set [answer v] to []
set [divider v] to (number base)
repeat until <(divider) > (decimal)> 
  set [divider v] to ((divider) * (number base))
end
set [divider v] to ((divider) / (number base))
repeat until <(divider) < [1]> 
  if <(divider) < (decimal)> then 
    set [answer v] to (join (answer) ([floor v] of ((decimal) / (divider))))
    set [decimal v] to ((decimal) - (([floor v] of ((decimal) / (divider))) * (divider)))
  else 
    set [answer v] to (join (answer) [0])
  end
  set [divider v] to ((divider) / (number base))
end

I think this works, set the variable “decimal” and the number base you want and it spits out the answer!

EDIT: somethings wrong, I just tried it with binary and it put a 2 in the answer! I'll check again

Should work now

set [decimal v] to [64]
set [number base v] to [2]
set [result v] to []
set [divider v] to (number base)
repeat until <(divider) > (decimal)> 
  set [divider v] to ((divider) * (number base))
end
set [divider v] to ((divider) / (number base))
repeat until <(divider) < [1]> 
  if <(divider) > (decimal)> then 
    set [result v] to (join (result) [0])
  else 
    set [result v] to (join (result) ([floor v] of ((decimal) / (divider))))
    set [decimal v] to ((decimal) - (([floor v] of ((decimal) / (divider))) * (divider)))
  end
  set [divider v] to ((divider) / (number base))
end

Whoa, this solution is way more complicated than it needs to be. Here's my script for converting a number to its equivalent in base 7.

set [number v] to [anything you want]
set [count v] to [0]
repeat until <(number) < [7]>
change [number v] by (-10)
change [count v] by (4)
end
change [number v] by ((((count) / (4)) * (10)) + (count))

Reign_Sky wrote:

Whoa, this solution is way more complicated than it needs to be. Here's my script for converting a number to its equivalent in base 7.

set [number v] to [anything you want]
set [count v] to [0]
repeat until <(number) < [7]>
change [number v] by (-10)
change [count v] by (4)
end
change [number v] by ((((count) / (4)) * (10)) + (count))

So start with number=14. Repeat loop sets number to 4 and count to 4 and ends. Then the change block sets number to number (4) + 14 which gives 18. So something is wrong there.