mstone326 wrote:

Yup, use an operator block and switch costume to costume # - 1. I tried to do the scratch blocks but I'm terrible at those things.

define previous costume
switch costume to ((costume #) - (1))

define next costume
switch costume to ((costume #) + (1))

gtoal wrote:

Doesnt work for costume 0 unless you do tricks with the mod operator and the list size, being careful with the 0/1 offset issue…

Charles12310 wrote:

mstone326 wrote:

Yup, use an operator block and switch costume to costume # - 1. I tried to do the scratch blocks but I'm terrible at those things.

switch costume to ((costume #) - (1))

switch backdrop to [previous backdrop v]

switch costume to (join [] [previous costume])//just set the first input blank(empty)
switch costume to (join [] [next costume])

asivi wrote:

It is posible to do this:

switch costume to (join [] [previous costume])//just set the first input blank(empty)
switch costume to (join [] [next costume])

And, of course, do not name any costume “previous costume” or “next costume”

switch costume to (join [1][])

Charles12310 wrote:

asivi wrote:

It is posible to do this:

switch costume to (join [] [previous costume])//just set the first input blank(empty)
switch costume to (join [] [next costume])

And, of course, do not name any costume “previous costume” or “next costume”

Also imagine if you named a costume “1” and it isn't “#1”.

What would happen if you use this?

switch costume to (join [1][])

Will it lead to the costume called 1 or costume #1?

Zeppry wrote:

There is no previous costume block, but there is a way to do it. Just get a subtract block under operators, and put in the first spot the costume # block from looks, and type 1 in the other space.

Charles12310 wrote:

asivi wrote:

It is posible to do this:

switch costume to (join [] [previous costume])//just set the first input blank(empty)
switch costume to (join [] [next costume])

And, of course, do not name any costume “previous costume” or “next costume”

Also imagine if you named a costume “1” and it isn't “#1”.

What would happen if you use this?

switch costume to (join [1][])

Will it lead to the costume called 1 or costume #1?

       (var)
switch costume to (var) // you drag the var on the thing where you can switch the costume ! :)

(var) // this variable will indicates the costume # what it should switch on

define previous costume
set [var v] to (costume #)     // You drag the costume # variable here
change [var v] by (-1)
switch costume to (var)

define previous costume
switch costume to ((costume #) + (-1))

define previous costume
switch backdrop to ((costume #) - (1))

play sound (var)
play sound (var) until done
<touching (var) ?>
(distance to (var))
(video [movement v] on (var))
([x - location v] of (var))

when (var) > (10)
when (var) key pressed
// But keep in mind these /\  when scripts maybe don't work so do
when [var v] > (10)
// This /\ works better

((var) of [Sprite1 v])
// but it might have the same prob so do \/
([var v] of [Sprite1 v])

//you can do this also \/
when I receive (var)
// but don't write this time the thing like \/ instead like this <-
when I receive [var v]