Replace letter () of () with ()

ipushpeople

LFOB wrote:
ipushpeople wrote:
Breck- wrote:
define replace letter (letter) of [text] with [string]
set [i v] to [1]
repeat (length of (text))
    add (letter (i) of (text)) to [tmp v]
    change [i v] by (1)
end
replace item (letter) of [tmp  v] with (string)
set [result v] to (tmp :: list) 
on a scale of “simple workaround” to “not simple workaround” i would rate that “very not simple workaround”

-D
All they have to do is copy the script and use the custom block to do what they need…
(And this is very simple programming anyway…)

well i don't understand it so i must be very stupid and am now very discouraged to use scratch.

and in my opinion telling someone to copy a block of code line by line is not a way to teach them how to program.

-D

A-KouZ1

Breck- wrote:

define replace letter (letter) of [text] with [string]
set [i v] to [1]
repeat (length of (text))
    add (letter (i) of (text)) to [tmp v]
    change [i v] by (1)
end
replace item (letter) of [tmp  v] with (string)
set [result v] to (tmp :: list)

…
you know when you replace a thing on list…
list reporter will be spacing

alexphan

/bump

ipushpeople wrote:
LFOB wrote:
ipushpeople wrote:
Breck- wrote:
define replace letter (letter) of [text] with [string]
set [i v] to [1]
repeat (length of (text))
    add (letter (i) of (text)) to [tmp v]
    change [i v] by (1)
end
replace item (letter) of [tmp  v] with (string)
set [result v] to (tmp :: list) 
on a scale of “simple workaround” to “not simple workaround” i would rate that “very not simple workaround”

-D
All they have to do is copy the script and use the custom block to do what they need…
(And this is very simple programming anyway…)
well i don't understand it so i must be very stupid and am now very discouraged to use scratch.

If you don't understand it, then try to understand and learn it instead of putting yourself down.

A-KouZ1

More logic blocks

set [mytext v] to [there's is manyyyyyyyyyyyyy typos here]
replace letter between (16) to (27) with [] of (mytext)//if u want remove a letter lol
set [mytext v] to (output::list)



define replace letter between (least) to (most) with (new) of (string)
delete [all v] of [output v]
set [i v] to [0]
repeat ((least)-(1))
    change [i v] by (1)
add (letter (i) of (string)) to [output v]
end
set [i v] to [0]
repeat ((most)-(least))
change [i v] by (1)
add (letter (i) of (new)) to [output v]
end
set [i v] to ((most)+(1))
repeat ((length of (string))-(most))
change [i v] by (1)
add (letter (i) of (string)) to [output v]
end

StrangeMagic32

Support! This would help edit cloud variables without overwriting others writing, would especially be helpful for online games, this way you don't have to use 1 variable per player, meaning more than 10 players can be on at once.

Last edited by StrangeMagic32 (Aug. 21, 2019 21:22:17)

itchdog

No support, this was added in 3.0, reportig to be closed

Botcho_Otkho

itchdog wrote:
this was added in 3.0

No.

Maybe you got confused with the

<[] contains []?::operators>

Last edited by Botcho_Otkho (Aug. 7, 2019 17:28:05)

15-MinuteGaming

Support. Although there is a very simple workaround, it is an extremely commonly encountered problem in programs

chrdagos

This is a interesting idea. Such block will allow for things like spell checking in projects.

(I like this idea)

CodeMasterExpert

What Breck- wrote doesn't work:

Breck- wrote:

define replace letter (letter) of (text) with(string)
set (i v) to[1]
repeat(length of (text)
add (letter (i) of (text)) to [tmp v]
change (i) by (1)
end
replace item (letter) of [tmp v] with (string)
set [result v] to (tmp)

chrdagos

bumpo

redgreenandblue

For the record, I still think this block would be really helpful.

sillyman987

redgreenandblue wrote:
I think there should be a
(replace letter () of [] with []::operators)
This would be extremely helpful for variables!
It would show in the block library as
(replace letter (1) of [jello world!] with [h]::operators)
If somebody knows a simple workaround that would also work.

Hi! So I gave this some thought, and I have two solutions decoding it into a list then encoding back, or using this:

when green flag clicked
<(Variable) = [35]>
set [ Variable] to (join (letter (1) of (Variable))  (join [6] (letter (2) of (Variable))))
<(Variable) = [365]>

NxNmultiply

Support because it is a fundamental array write operation, which Scratcch doesn't currently have.

littleBitsman1

redgreenandblue wrote:
I think there should be a
(replace letter () of [] with []::operators)
This would be extremely helpful for variables!
It would show in the block library as
(replace letter (1) of [jello world!] with [h]::operators)
If somebody knows a simple workaround that would also work.

they should add that
smh they havent done that yet ;-;

Last edited by littleBitsman1 (March 22, 2021 14:08:40)

ScratchCat8464

Simplified way

Run without screen refresh

define  Replace letter (a) of (b) with (c)
set [count v] to [0]
set [result v] to []
repeat (length of (b))
change [count v] by (1)
if <(count) = (a)> then 
set [result v] to (join (result) (c))
else
set [result v] to (join (result) (letter (count) of (b))
end
end

Replace letter (6) of [hello?] with [!]
say <(result) = [hello!]>

Last edited by ScratchCat8464 (June 26, 2021 04:39:19)

elip100

Breck- wrote:

define replace letter (letter) of [text] with [string]
set [i v] to [1]
repeat (length of (text))
    add (letter (i) of (text)) to [tmp v]
    change [i v] by (1)
end
replace item (letter) of [tmp  v] with (string)
set [result v] to (tmp :: list)

thank you!!! this was very usefull!

Last edited by elip100 (July 7, 2021 14:30:46)

ScratchCat8464

elip100 wrote:

Breck- wrote:

define replace letter (letter) of [text] with [string]
set [i v] to [1]
repeat (length of (text))
    add (letter (i) of (text)) to [tmp v]
    change [i v] by (1)
end
replace item (letter) of [tmp  v] with (string)
set [result v] to (tmp :: list)

thank you!!! this was very usefull!

in my method you don't need to create a list

PenguinLover1123

redgreenandblue wrote:
I think there should be a
(replace letter () of [] with []::operators)
This would be extremely helpful for variables!
It would show in the block library as
(replace letter (1) of [jello world!] with [h]::operators)
If somebody knows a simple workaround that would also work.

OMEGA SUPPORT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! because it's useful

Breck- wrote:

define replace letter (letter) of [text] with [string]
set [i v] to [1]
repeat (length of (text))
    add (letter (i) of (text)) to [tmp v]
    change [i v] by (1)
end
replace item (letter) of [tmp  v] with (string)
set [result v] to (tmp :: list)

it's a stack, not a reporter

ScratchCat8464

A-KouZ1 wrote:

More logic blocks

set [mytext v] to [there's is manyyyyyyyyyyyyy typos here]
replace letter between (16) to (27) with [] of (mytext)//if u want remove a letter lol
set [mytext v] to (output::list)



define replace letter between (least) to (most) with (new) of (string)
delete [all v] of [output v]
set [i v] to [0]
repeat ((least)-(1))
    change [i v] by (1)
add (letter (i) of (string)) to [output v]
end
set [i v] to [0]
repeat ((most)-(least))
change [i v] by (1)
add (letter (i) of (new)) to [output v]
end
set [i v] to ((most)+(1))
repeat ((length of (string))-(most))
change [i v] by (1)
add (letter (i) of (string)) to [output v]
end

easiest method:

define replace letter between (least) to (most) with (new) of (string)
set [output v] to []
set [count v] to [0]
repeat (length of (string))
change [count v] by (1)
if <(count) = (least)> then 
set [output v] to (join (output) (new))
else
if <not <<((least) - (1)) < (count)> and <((most) + (1)) > (count)>>> then
set [output v] to (join (output) (letter (count) of (string))
end
end
end

replace letter between (4) to (6) with [] of [easiwyy!]
say (output)
//output = easy!

Discuss Scratch