mitchboy wrote:

8solarplanets wrote:

But what if we wanted, for example 84 ^ 59? There's no block for that.

There now is.

This project.

EDIT: 84 ^ 59 = 3.40782965354148e+113. Boom.

define exponentify (x), (y)
set [result v] to [1]
if <(y) > [0]> then
repeat (y)
set [result v] to ((result) * (x))
end
else
repeat (y)
set [result v] to ((result) / (x))

theonlygusti wrote:

Support, even though

((base) ^ (log) :: operators)

is exactly the same as

([10^ v] of ((base) * ([log v] of (log) :: operators)) :: operators)

Iditaroid wrote:

RalphMath wrote:

Please, please, please add this as an operator just like +-*/ it's a real limitation when teaching a lot of math concepts not to have exponentiation.

I know this is technically necroposting but you raise a good point! An exponent block would certainly make things easier for teachers working with Scratch!

lalala3 wrote:

I just figured out something. Neither of the workarounds are perfect. The one using loops has issues with raising numbers to negative or fractional powers, while the other workaround (using logs) doesn't work if the base isn't positive. I thus propose the following solution:

Define (base) ^ (exponent)
if <(base :: custom) > (0)> then
    set [answer v] to ([10 ^ v] of ((exponent) * ([log v] of (base))))
else
    if <((exponent) mod (1)) = (0)> then
        set [answer v] to [1]
        repeat ([abs v] of (exponent))
            set [answer v] to ((answer) * (base))
        end
        if <(exponent) < (0)> then
            set [answer v] to ((1)/(answer))
        end
    else
        set [answer v] to [undefined]
    end
end

Can we have a proper exponent block now? Please?

mitchboy wrote:

kayybee wrote:

The short version works for all real numbers, the long one doesn't.

Actually, 3.14 ^ 3.14 results in 30.959 on my custom block (about seven posts above). Try it. It just doesn't work with negative numbers or fractions. And my project barely involves any heavy scripting or math at all. All you need is:
- three variables
- a repeat block
- a subtraction and a multiplication block
- a set variable block

That's it. It took me like two minutes.

define exp (value, power)
if <<[value] < [0 ]> and << [power] mod [1]> > [0]>> then
set [answer] to [ ]
else
set [answer] to ([e^ v] of ([power] * ([ln v] of ([abs v] of [value])))
if <([value] < [0]) and (([power] mod [2]) = [1])> then
set [answer] to ([answer] * [-1])
end

define x to the power of y

if <([10^ v] of (( power) * ([log v] of ( base))) :: operators) = (( base) ^ ( power) :: operators)> then
say [This makes sense]
else
say [I think the kumquats made this bug]
end

(((((((((...) * (0)) * (0)) * (0)) * (0)) * (0)) * (0)) * (0)) * (0))

Sparkfunny wrote:

100% support!

(((y) / (2)) * ((x) * (x)))

savaka wrote:

drmcw wrote:

xlk wrote:

yes, but same can be said of the change x/y by and go to blocks… They aren't necessary, but for new scratchers are a great help.

Yes, but how many projects need a x^y block?

I was thinking of making a calculator project.

define (x) ^ (y)
set [output v] to [0]
repeat (y)
change [output v] by (([sin v] of (y)) / (([floor v] of (x)) + ((length of ((y) * (10))) - ([abs v] of ((x) + ((y) - ((x) / (4))))))))

Owengren wrote:

savaka wrote:

drmcw wrote:

xlk wrote:

yes, but same can be said of the change x/y by and go to blocks… They aren't necessary, but for new scratchers are a great help.

Yes, but how many projects need a x^y block?

I was thinking of making a calculator project.

My project needs one! But, I have a workaround:

define (x) ^ (y)
set [output v] to [0]
repeat (y)
change [output v] by (([sin v] of (y)) / (([floor v] of (x)) + ((length of ((y) * (10))) - ([abs v] of ((x) + ((y) - ((x) / (4))))))))

mitchboy wrote:

kayybee wrote:

The short version works for all real numbers, the long one doesn't.

Actually, 3.14 ^ 3.14 results in 30.959 on my custom block (about seven posts above). Try it. It just doesn't work with negative numbers or fractions. And my project barely involves any heavy scripting or math at all. All you need is:
- three variables
- a repeat block
- a subtraction and a multiplication block
- a set variable block

That's it. It took me like two minutes.

([10^ v] of ([second] * ([log v] of [first]) :: pen) :: operators )

Owengren wrote:

savaka wrote:

drmcw wrote:

xlk wrote:

yes, but same can be said of the change x/y by and go to blocks… They aren't necessary, but for new scratchers are a great help.

Yes, but how many projects need a x^y block?

I was thinking of making a calculator project.

My project needs one! But, I have a workaround:

define (x) ^ (y)
set [output v] to [0]
repeat (y)
change [output v] by (([sin v] of (y)) / (([floor v] of (x)) + ((length of ((y) * (10))) - ([abs v] of ((x) + ((y) - ((x) / (4))))))))