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- gtoal
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Scratcher
1000+ posts
Crazy Hard Math Problem Week #4 [solved]
Insane!!!: Write a formula that uses two consecutive positive integers, a and b, to always equal a prime number. (Note: The formula should not always equal one number )
Edit: ^ Above only requires the formula to work until the numbers 3 and 4
a+b, where b=a+1…
1+2=3
2+3=5
3+4=7
Or did I misunderstand the question? :-)
- ev3coolexit987654
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Scratcher
1000+ posts
Crazy Hard Math Problem Week #4 [solved]
wow… i can't believe i did all thisInsane!!!: Write a formula that uses two consecutive positive integers, a and b, to always equal a prime number. (Note: The formula should not always equal one number )
Edit: ^ Above only requires the formula to work until the numbers 3 and 4
a+b, where b=a+1…
1+2=3
2+3=5
3+4=7
Or did I misunderstand the question? :-)
- goldfish678
-
Scratcher
1000+ posts
Crazy Hard Math Problem Week #4 [solved]
Preeeeetty sure this is it:
Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17
Idk maybe I messed up something with the parentheses but I guess it's fine
Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17
Idk maybe I messed up something with the parentheses but I guess it's fine
- ev3coolexit987654
-
Scratcher
1000+ posts
Crazy Hard Math Problem Week #4 [solved]
Preeeeetty sure this is it:lol? Much simpler ways for not so easy… ex. join(3)(4)/sqrt(4)
Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17
Idk maybe I messed up something with the parentheses but I guess it's fine
- WooHooBoy
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Scratcher
1000+ posts
Crazy Hard Math Problem Week #4 [solved]
Preeeeetty sure this is it:I admire your dedication
Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17
Idk maybe I messed up something with the parentheses but I guess it's fine

- thegoldfish
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Scratcher
100+ posts
Crazy Hard Math Problem Week #4 [solved]
join is a math function?Preeeeetty sure this is it:lol? Much simpler ways for not so easy… ex. join(3)(4)/sqrt(4)
Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17
Idk maybe I messed up something with the parentheses but I guess it's fine

thank youPreeeeetty sure this is it:I admire your dedication
Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17
Idk maybe I messed up something with the parentheses but I guess it's fine
- ev3coolexit987654
-
Scratcher
1000+ posts
Crazy Hard Math Problem Week #4 [solved]
they never said it had to be a math functionjoin is a math function?Preeeeetty sure this is it:lol? Much simpler ways for not so easy… ex. join(3)(4)/sqrt(4)
Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17
Idk maybe I messed up something with the parentheses but I guess it's finethank youPreeeeetty sure this is it:I admire your dedication
Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17
Idk maybe I messed up something with the parentheses but I guess it's fine
anyway (3^4)-(4^3)- mUSTfOLLOWeVERYONE
-
Scratcher
13 posts
Crazy Hard Math Problem Week #4 [solved]
(abs(a) / a) + 4= prime
It will alternate between 3 and 5
The OP said it should not always be the same answer. This alternates between 2 answers
It will alternate between 3 and 5
The OP said it should not always be the same answer. This alternates between 2 answers

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