Discuss Scratch

gtoal
Scratcher
1000+ posts

Crazy Hard Math Problem Week #4 [solved]

-Incognito- wrote:

Insane!!!: Write a formula that uses two consecutive positive integers, a and b, to always equal a prime number. (Note: The formula should not always equal one number )

Edit: ^ Above only requires the formula to work until the numbers 3 and 4

a+b, where b=a+1…

1+2=3
2+3=5
3+4=7

Or did I misunderstand the question? :-)
ev3coolexit987654
Scratcher
1000+ posts

Crazy Hard Math Problem Week #4 [solved]

gtoal wrote:

-Incognito- wrote:

Insane!!!: Write a formula that uses two consecutive positive integers, a and b, to always equal a prime number. (Note: The formula should not always equal one number )

Edit: ^ Above only requires the formula to work until the numbers 3 and 4

a+b, where b=a+1…

1+2=3
2+3=5
3+4=7

Or did I misunderstand the question? :-)
wow… i can't believe i did all this
goldfish678
Scratcher
1000+ posts

Crazy Hard Math Problem Week #4 [solved]

Preeeeetty sure this is it:

Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17

Idk maybe I messed up something with the parentheses but I guess it's fine
ev3coolexit987654
Scratcher
1000+ posts

Crazy Hard Math Problem Week #4 [solved]

goldfish678 wrote:

Preeeeetty sure this is it:

Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17

Idk maybe I messed up something with the parentheses but I guess it's fine
lol? Much simpler ways for not so easy… ex. join(3)(4)/sqrt(4)
WooHooBoy
Scratcher
1000+ posts

Crazy Hard Math Problem Week #4 [solved]

goldfish678 wrote:

Preeeeetty sure this is it:

Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17

Idk maybe I messed up something with the parentheses but I guess it's fine
I admire your dedication
thegoldfish
Scratcher
100+ posts

Crazy Hard Math Problem Week #4 [solved]

ev3coolexit987654 wrote:

goldfish678 wrote:

Preeeeetty sure this is it:

Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17

Idk maybe I messed up something with the parentheses but I guess it's fine
lol? Much simpler ways for not so easy… ex. join(3)(4)/sqrt(4)
join is a math function?

WooHooBoy wrote:

goldfish678 wrote:

Preeeeetty sure this is it:

Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17

Idk maybe I messed up something with the parentheses but I guess it's fine
I admire your dedication
thank you
ev3coolexit987654
Scratcher
1000+ posts

Crazy Hard Math Problem Week #4 [solved]

thegoldfish wrote:

ev3coolexit987654 wrote:

goldfish678 wrote:

Preeeeetty sure this is it:

Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17

Idk maybe I messed up something with the parentheses but I guess it's fine
lol? Much simpler ways for not so easy… ex. join(3)(4)/sqrt(4)
join is a math function?

WooHooBoy wrote:

goldfish678 wrote:

Preeeeetty sure this is it:

Easy, 3 + 4 + 3
Not So Easy, ((((((3*4)*3)/4)*3)*((4-3)-(4-3)-(4-3)-(4-3))*(3-4))-3)/3 = 17

Idk maybe I messed up something with the parentheses but I guess it's fine
I admire your dedication
thank you
they never said it had to be a math function anyway (3^4)-(4^3)
mUSTfOLLOWeVERYONE
Scratcher
13 posts

Crazy Hard Math Problem Week #4 [solved]

(abs(a) / a) + 4= prime

It will alternate between 3 and 5

The OP said it should not always be the same answer. This alternates between 2 answers

Powered by DjangoBB